Answer:
2kg
Step-by-step explanation:
Let the sum of the other 2 bricks be R. Given that the heaviest brick weighs 2/3 times as much as the other 2 bricks in total, then the weight of the heaviest brick H in terms of the weight of the other 2 will be
H = 2/3 * R
= 2R/3
Given that the 3 bricks weigh 5kg in total then,
2R/3 + R = 5
Multiply through the equation by 3
2R + 3R = 15
5R = 15
Divide both sides by 5
R = 15/5
= 3
The weight of the heaviest brick is 2R/3. Since R = 3, the heaviest block weighs
= 2 * 3/3
= 2kg
Answer:
funny I have this question and I thought it was D
Answer:

Step-by-step explanation:
Slant Height = 10 cm
Base Edge = 12 cm
<u>Finding the Height using Pythagorean Theorem:</u>
![\sf c^2 = a^2 + b^2 \\\\Where \ c = 10\ cm , b = 6\ cm [Half of 12] \ and \ a \ is \ height\\\\10^2 = a^2 + 6^2\\\\100=a^2 +36\\\\100-36 = a^2\\\\64 = a^2\\\\Taking \ sqrt \ on \ both \ sides\\\\Height= 8 \ cm](https://tex.z-dn.net/?f=%5Csf%20c%5E2%20%3D%20a%5E2%20%2B%20b%5E2%20%5C%5C%5C%5CWhere%20%5C%20c%20%3D%2010%5C%20cm%20%2C%20b%20%3D%206%5C%20cm%20%5BHalf%20of%2012%5D%20%5C%20and%20%5C%20a%20%5C%20is%20%5C%20height%5C%5C%5C%5C10%5E2%20%3D%20a%5E2%20%2B%206%5E2%5C%5C%5C%5C100%3Da%5E2%20%2B36%5C%5C%5C%5C100-36%20%3D%20a%5E2%5C%5C%5C%5C64%20%3D%20a%5E2%5C%5C%5C%5CTaking%20%5C%20sqrt%20%5C%20on%20%5C%20both%20%5C%20sides%5C%5C%5C%5CHeight%3D%208%20%5C%20cm)
![\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Crule%5B225%5D%7B225%7D%7B2%7D)
<u>Now, Finding the volume:</u>

![\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Crule%5B225%5D%7B225%7D%7B2%7D)
Hope this helped!
<h2>~AnonymousHelper1807</h2>
Answer:
ano hindi po ma hintindihan po hindi paano po yan masasagutan
Answer:
n = - 6
Step-by-step explanation:
Given k(x) then k(x) + n is a vertical translation of k(x)
• If n > 0 then a shift up of n units
• If n < 0 then a shift down of n units
Here k(x) has been shifted from (0, 0 ) to (0, - 6 )
That is a shift down of 6 units, then
p(x) = k(x) - 6
That is n = - 6