Answer:
It would be the first one or second one
Step-by-step explanation:
the answer is up ahead
The chance of student 1's birthday being individual is 365/365 or 100%.
Then the chance of student 2's birthday being different is 364/365.
Then it's narrowed down to 363/365 for student 3 and so on until you get all 10 students.
If you multiply all these values together, the probability would come out at around 0.88305182223 or 0.88.
To get all the same birthday you'd have to the chance of one birthday, 1/365 and multiply this by itself 10 times. This will produce a very tiny number. In standard form this would be 2.3827x10'-26 or in normal terms: 0.23827109210000000000000000, so very small.
Answer:
You are selecting marbles with replacement. The marble selections (trials) are independent and the marble selection follows the binomial distribution.
The probability of selecting a red marble the first time is 1313.
(This is because 4 out of 12 marbles are red and412412 reduces to 1313.
The probability of selecting a red marble the second time is 1313.
The marble selections are independent and you can multiply the two probabilities to get the following:
probability of getting 2 reds = (13)2(13)2
=19=19.
So the probability of getting two reds is 1919.
Answer:
b. -84
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtract Property of Equality
<u>Algebra I</u>
Step-by-step explanation:
<u>Step 1: Define</u>
<u />
<u />
<u />
<u>Step 2: Solve for </u><em><u>a</u></em>
- Addition Property of Equality:
- [Simplify] Add:

- Multiplication Property of Equality:

- [Simplify] Multiply:

<u>Step 3: Check</u>
<em>Plug in a into the original equation to verify it's a solution.</em>
- Substitute in <em>a</em>:

- [Frac] Divide:

- Subtract:

Here we see that 5 does indeed equal 5.
∴ a = -84 is the solution to the equation.