Yes, ode45 can be used for higher-order differential equations. You need to convert the higher order equation to a system of first-order equations, then use ode45 on that system.
For example, if you have
... u'' + a·u' + b·u = f
you can define u1 = u, u2 = u' and now you have the system
... (u2)' + a·u2 + b·u1 = f
... (u1)' = u2
Rearranging, this is
... (u1)' = u2
... (u2)' = f - a·u2 - b·u1
ode45 is used to solve each of these. Now, you have a vector (u1, u2) instead of a scalar variable (u). A web search regarding using ode45 on higher-order differential equations can provide additional illumination, including specific examples.
Answer:
A. 23+(6-1)x-3
B. 93
Step-by-step explanation:
a) Nth term = F + (N - 1) x D, where F=First term, N=Number of terms, D=Common difference
6th row = 23 + (6 - 1) x -3
= 23 + (5) x -3
= 23 + (-15)
= 8 - number of boxes in the top row.
b) Sum = N/2[2F + (N - 1) x D]
= 6/2[2*23 + (6 - 1) x -3]
= 3 [46 + (5) x -3 ]
= 3 [46 + -15 ]
= 3 [ 31 ]
= 93 - total number of boxes in the entire display.
Hope this helps! Its 3:25 AM for me too so I know how you feel.
Step-by-step explanation:<u>The slope calculator helps find the slope of any line through two given ... the slope of the line passing through the points (3,8) and (-2, 10) . ... A 1/20 slope is one that rises by 1 unit for every 20 units traversed horizontally.</u>
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Answer:
C
Step-by-step explanation:
164.7/8.6 = 19.15
about 20 miles per gallon
Answer:
Inequality : 4x+8 < 120
x<28
Step-by-step explanation:
Hi, to answer this question we have to apply the next formula:
Perimeter of a rectangle (P)= 2 length +2 width
Where:
Width = x
Length = x+4
Replacing with the values given
P = 2 (x+4) + 2x
P = 2x+8+2x
P=4x+8
Since the perimeter of the rectangle must be less than 120:
4x+8 < 120
Solving for x
4x<120-8
4x<112
x<112/4
x<28
Feel free to ask for more if needed or if you did not understand something.
