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horrorfan [7]
3 years ago
7

Round 185 to the nearest hundreds​

Mathematics
2 answers:
Mashcka [7]3 years ago
6 0

Answer:

200

Step-by-step explanation:

185

The 1 is in the hundreds place so we look at the 8

8>5 so we need to round the 1 up to 2

185 rounds to 200

Anna007 [38]3 years ago
3 0

Answer:

200

Step-by-step explanation:

in 185 you just want to look at the 85 for right now because the 1 is the hundreds place. You then ask yourself, is 85 closer to 0 or 100? Since 85 is closer to 100, you must round up to 200.

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12. Zachary Tylar 72% commission? earns commission on sales of $4,255. What is his commission ​
ioda

Answer:

$3063.6

Step-by-step explanation:

72% of $4,255 = $3063.6

The formula for finding percents is number x percent ÷ 100.

4,255 x 72 ÷  100 = 3063.6

8 0
2 years ago
Help me on my math pwease
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Answer:

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Step-by-step explanation:

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3 years ago
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6 0
3 years ago
I need help on the following questions.
Zigmanuir [339]
For the first one, you just need to divide the amount of feet by 3 to get the amount of yards (there are three feet in a yard). 

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Second, you just need to multiply the amount of centimeters by 10 (there are 10 millimeters in a centimeter).

16 * 10 = 160

The butterfly has a wingspan of 160mm.

Third, the measurements are indeed 
7. =
8. =
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10. >
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Fourth, you just need to know your conversion factors.
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2. There are 1000 meters in a kilometer. 2350 / 1000 = 2.35 km
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8 0
3 years ago
A random sample is selected from a normally distributed population. The following sample statistics are obtained: n = 20, = 30,
Flura [38]

Answer:

b) The margin of error is approximately 3.24

e) The critical value is 1.7921.

Step-by-step explanation:

<u>Step(i</u>):-

Given sample size 'n' =20

Given sample standard deviation 's' = 10

<u><em> Margin of error </em></u>

<u><em>The margin of error is determined by</em></u>

<u><em /></u>M.E = \frac{t_{\alpha } S.D }{\sqrt{n} }<u><em /></u>

<em>The level of significance ∝ =0.95</em>

<em>The degrees of freedom = n-1 = 20-1=19</em>

t₀.₉₅ = 1.729

M.E = \frac{1.729 X10 }{\sqrt{20} }

Margin of error = 3.866

Step(ii):-

<u><em> Margin of error </em></u>

<u><em>The margin of error is determined by</em></u>

<u><em /></u>M.E = \frac{t_{\alpha } S.D }{\sqrt{n} }<u><em /></u>

<u><em>Given another sample size n =30</em></u>

<em>The level of significance ∝ =0.95</em>

<em>The degrees of freedom = n-1 = 30-1=29</em>

t₀.₉₅ = 1.70

M.E = \frac{1.7021 X10 }{\sqrt{30} } =3.24

<u><em>Margin of error = 3.24</em></u>

5 0
3 years ago
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