What is the point of intersection when the system of equations below is graphed on the coordinate plane?
2 answers:
Answer with explanation:
The two system of equation which are graphed on coordinate plane :
→x -y =1
y=x-1
→y-x=1
y=x+1
⇒Comparing with Slope intercept form of Line which is y= m x +c,
→m=1 for both the lines
As, the two lines has same slope , so they are parallel.Parallel lines never Intersect.
⇒The two system of equation have no solution as:
Option A:→ No Intersection Point
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An equation in the form of slope intercept is written as y=mx+b. That means that we need to get y positive, which we can do by adding 3y to each side, and then subtracting 3 from each side to get y by itself. Doing all of these steps, the equation becomes 3y=5x-3. But, we're not done because we still need to get y equal to one, which we can do by dividing each side of the equation by 3. This makes the equation become y=5/3x-1.
The graph of the equation looks like this:
The graph of the equation looks like this:
Hello from MrBillDoesMath!
Answer:
4/sin(80)
which is approximately 4.06
Discussion:
From the triangle, not drawn too accurately (see attachment)
sin(80) = side opposite /hypotenuse =>
sin (80) = 4/c => multiply both sides by "c"
c sin(80) = 4/c * c =>
c sin(80) = 4 => divide both sides by sin(80)
c = 4/sin(80)
and 4/sin(80) is approximately 4.06
Thank you,
MrB
