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2 years ago

X^4-6x^2+8(Type 2 of quadratic equation)

Mathematics

1 answer:

Alex Ar [27]2 years ago

5 0

Step-by-step explanation:

x⁴ - 6x² + 8

= (x² - 4)(x² - 2)

= (x + 2)(x - 2)(x² - 2).

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Which is perpendicular to the line y=-3x-8y

atroni [7]

Answer:

I believe the answer is y = -7/3x

Step-by-step explanation:

When you rearrange the equation, y = -3x - 8y, you will get -7y = -3x.

We want the equation to be equal to y by itself. So we divide -7 from both sides, giving us the equation y = 3/7x.

The graph that is perpendicular to y = 3/7x is it's reciprocal: y = -7/3x

4 0

2 years ago

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To rent a certain meeting room, a college charges a reservation fee of $19 and an additional fee of $4 per hour. The chemistry c

prisoha [69]

Answer:

t = 5

Step-by-step explanation:

$19 + 4t = 39$
$4t = 20$ Subtract 19 from 39
$\frac{4t}{4} = \frac{20}{4}$ Divide by 4
$t = 5$

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3 years ago

Explain how to the problem with the model. I do not want any unexplained answer I will report them!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Sever21 [200]

hewo

Step-by-step explanation:

they dragged me here to answer this question also no I don't know the answer... sorry

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2 years ago

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Evaluate cube root of 5 multiplied by square root of 5 over cube root of 5 to the power of 5.

Andre45 [30]

Answer:

Option d) 5 to the power of negative 5 over 6 is correct.

$\dfrac{\sqrt[3]{\bf 5} \times \sqrt{\bf 5}}{\sqrt[3]{\bf 5^{\bf 5}}}= 5^{\frac{\bf -5}{\bf 6}}$

Above equation can be written as 5 to the power of negative 5 over 6.

ie, $5^\frac{\bf -5}{\bf 6}$

Step-by-step explanation:

Given that cube root of 5 multiplied by square root of 5 over cube root of 5 to the power of 5.

It can be written as below

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= \dfrac{5^{\frac{1}{3}} \times 5^{\frac{1}{2}}}{5^{\frac{5}{3}}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= \dfrac{5^{\frac{1}{3}+\frac{1}{2}}}{5^{\frac{5}{3}}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= \dfrac{5^{\frac{2+3}{6}}}{5^{\frac{5}{3}}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= 5^{\frac{5}{6}} \times 5^{\frac{-5}{3}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= 5^{\frac{5-10}{6}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{5^5}= 5^{\frac{-5}{6}}$

Above equation can be written as 5 to the power of negative 5 over 6.

7 0

3 years ago

If x^2=y^2+z^2 what does x equal?

Zepler [3.9K]

Answer:

$\displaystyle x = \sqrt{y^2 + z^2}$

General Formulas and Concepts:

Pre-Algebra

Equality Property

Algebra i

Terms/Coefficients

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle x^2 = y^2 + z^2$

Step 2: Solve for x

[Equality Property] Square root both sides: $\displaystyle x = \sqrt{y^2 + z^2}$

3 0

2 years ago