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jarptica [38.1K]
3 years ago
10

What is the product of 1 2/3 and −3 1/2 ?

Mathematics
2 answers:
Zinaida [17]3 years ago
8 0

1/2*-3 1/2 = -21/4  = -5 1/4= <em>-5.25</em>

I hope this helps!!


Tanzania [10]3 years ago
3 0

Answer:

-5 5/6

Step-by-step explanation:

you change 1 2/3 to 5/3 and change-3 1/2 to 7/2.

then mutiply that which equals 35/6 then divide 35 by 6 which equals -5 5/6

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Does the table represent a linear function? Why or why not.
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What are the coordinates of R' after a dilation by a scale factor of 3, centered at the origin, followed by the translation (x,
emmainna [20.7K]

9514 1404 393

Answer:

  C.  (9, 18)

Step-by-step explanation:

Given R(3, 5), a dilation by a factor of 3 will multiply each coordinate to give ...

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Then the translation up by 3 will give you the image coordinates ...

  (x, y) ⇒ (x, y+3)

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The coordinates of R' are (9, 18), matching choice C.

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<em>Comment on multiple choice answers</em>

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8 0
3 years ago
Let's find2. 1+5 3First write the addition with a common denominator.Then add.12— +51-4-13Х5
emmasim [6.3K]
Answer:\frac{2}{5}+\frac{1}{3}=\frac{6}{15}+\frac{5}{15}=\frac{11}{15}Explanation:

The given addition exercise is:

\frac{2}{5}+\frac{1}{3}

The LCM of the denominator (5 and 3) = 15

Multiply 2/5 by 3/3

\frac{2}{5}=\frac{2\times3}{5\times3}=\frac{6}{15}

Multiply 1/3 by 5/5

\frac{1}{3}=\frac{1\times5}{3\times5}=\frac{5}{15}

The addition becomes

\frac{6}{15}+\frac{5}{15}=\frac{11}{15}

Therefore, we can fill in the vacant boxes as shown below:

\frac{2}{5}+\frac{1}{3}=\frac{6}{15}+\frac{5}{15}=\frac{11}{15}

4 0
1 year ago
Please answer this mathematical problem.
n200080 [17]

x = total amount of gumballs

let's start subtracting the balls she's giving away

\stackrel{total}{x}-\stackrel{\textit{to jaysen}}{\cfrac{x}{2}}\implies \stackrel{\textit{what's left}}{\cfrac{x}{2}}~\hfill \stackrel{\textit{half of what's left to Marinda}}{\cfrac{~~ \frac{x}{2}~~}{2}\implies \cfrac{x}{4}} \\\\\\ \stackrel{\textit{what was left minus Marinda's}}{\cfrac{x}{2}-\cfrac{x}{4}\implies \stackrel{\textit{what's left}}{\cfrac{x}{4}}}~\hfill ~\hfill \stackrel{\textit{a third of what's left to Zack}}{\cfrac{~~ \frac{x}{4}~~}{3}\implies \cfrac{x}{12}}

\stackrel{\textit{what was left minus Zack's}}{\cfrac{x}{4}-\cfrac{x}{12}\implies \stackrel{\textit{what's left}}{\cfrac{x}{6}}}~\hfill \stackrel{\textit{her sister gets 5 balls of what's left}}{ \cfrac{x}{6}-5 }

and we also know that after all that has been subtracted, she's only left with 5, so we can say that

\stackrel{\textit{what's finally left}}{\cfrac{x}{6}-5}~~ = ~~\stackrel{\textit{what's finally left}}{5}\implies \cfrac{x}{6}=10\implies \boxed{x = 60}

5 0
2 years ago
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