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ahrayia [7]
2 years ago
8

Two random samples were taken to determine how often people in a community listen to local radio station each month. The first s

ample survey and 15 people as they exited the bank on Main Street. The first sample found that the mean number of hours they listen to the radio each month was 20. The second sample surveyed every six person as ta exited the local grocery store until 100 people were surveyed. The second sample found that the mean number of hours they listen to the radio was 12. Which statements are true? Check all that apply.
Mathematics
1 answer:
Lelechka [254]2 years ago
8 0

Question:

Two random samples were taken to determine how often people in a community listen to the local radio station each month.

The first sample surveyed 15 people as they exited the bank on Main Street. The first sample found that the mean number of hours they listened to the radio each month was 20.

The second sample surveyed every sixth person as they exited the only local grocery store until 100 people were surveyed. The second sample found that the mean number of hours they listened to the radio each month was 12.

Which statements are true? Check all that apply.

A) The second sample is random.

B) The second sample is likely to be more representative of the population.

C) The first sample is likely to be more representative of the population.

D) The second sample will give a better representation because is it larger.

E) The first sample will give a better representation because it is smaller.

F) Community members are more likely to listen to the radio station an average of 12 hours a month than 20 hours a month.

Answer:

Options A, B, D, and F

Step-by-step explanation:

A) The second sample is random because in the second sample, people were surveyed at random. Every sixth person that exited the grocery store was surveyed and this selection represents an unbiased sampling method of the general population.

B) The second sample is likely to be more representative of the population, this is because, the sampling method was unbiased and it also contains a larger sample size than first sample.

D) The second sample will give a better representation because is it larger. Sample size is an important factor in a research. A large sample size gives a more accurate mean value than a small sample size.

F) Community members are more likely to listen to the radio station an average of 12 hours a month than 20 hours a month. This is because the research with the larger sample size is accepted instead of that of the smaller sample size. Also the second sample is likely to be more representative of the general population.

Options C and E are incorrect.

Thus, we can say that options A, B, D & F are correct.

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3 years ago
The perimeter of a rectangular field is 354 yards. If the width of the field is 82 yards, what is its length
GenaCL600 [577]
Length is 95 yards.

The perimeter of a rectangle is the sum of four sides. The four sides are either its length or width.

A rectangle has four sides where its angles are all right angles and its opposite sides are congruent or of equal size.

Perimeter = 2length + 2width ==> P = 2L   + 2W

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4 0
3 years ago
Read 2 more answers
Water is leaking out of an inverted conical tank at a rate of 6800 cubic centimeters per min at the same time that water is bein
Bad White [126]

Answer:

The rate at which water is being pumped into the tank is 13,913.27 cubic centimetre per minute

Step-by-step explanation:

Given that, the height of the conical tank is 13 meters and diameter is 3 meters.

Radius = \frac32 meters

\therefore \frac{radius }{height}=\frac {\frac{3}{2}}{13}

\Rightarrow \frac{radius }{height}=\frac {3}{26}

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The volume of the cone is   V=\frac13 \pi r^2 h

Now putting r=\frac{3}{26} h

V=\frac13 \pi (\frac3{26}h)^2 h

\Rightarrow V=\frac{3}{676} \pi h^3

Differentiating with respect to t

\frac{dV}{dt}=\frac{3}{676}\pi .3h^2 \frac{dh}{dt}

\Rightarrow \frac{dV}{dt}=\frac{9}{676}\pi h^2 \frac{dh}{dt}

Given that, the water level is rising at a rate of 17 cm per minute when the height 1 meter= 100 cm .i.e \frac{dh}{dt}=17 cm/min

Putting \frac{dh}{dt}=17  

\frac{dV}{dt}=\frac{9}{676}\pi h^2 \times 17

\frac{dV}{dt}|_{h=100}=\frac{9}{676}\pi (100)^2 \times 17

             ≈7,113 cubic centimetre per minute

The volume of water increases 7,113 cubic centimetre per minute while 6,800 cubic centimetre per minute is leaking out.

It means the required rate at which water is being pumped into the tank is

=(7,113+6,800)cubic centimetre per minute

=13,913 cubic centimetre per minute

           

   

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