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Elodia [21]
3 years ago
12

Lilia meets her cousin Carmen and starts chatting a few minutes later. Mariene, who is Carmen's cousin, can affirm that:

Mathematics
1 answer:
astra-53 [7]3 years ago
8 0

Answer:

B

Step-by-step explanation:

They are all cousins.

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N
GrogVix [38]

9514 1404 393

Answer:

  (d)   f(x) = 2x^2 - 16x + 35

Step-by-step explanation:

The x-coordinate of the extreme will be found at ...

  x = -b/(2a)

where the function is f(x) = ax²+bx+c.

The extreme will be a minimum when a > 0. (eliminates choices A and B)

The x-coordinates of the extremes are ...

  C: -(-4)/(2(4)) = 1/2

  D: -(-16)/(2(2)) = 4 . . . . . matches the requirement

The appropriate choice is ...

  f(x) = 2x^2 - 16x + 35

3 0
3 years ago
I NEED UR HELP ILL BE BRAINLISTING YALL!
Solnce55 [7]
Original price = $20

Markup percentage = 65

Markup amount = 0

What is the profit?

65% of 20 = $12

Therefore Markup amount = $12

Profit = Original price + markup amount
= $20 + $12
= $32

7 0
3 years ago
Read the sentence below about the Chicago fire of 1871. The city of Chicago was restored quickly after the fire. Which revision
ICE Princess25 [194]

Answer:

A:The city of Chicago was restored after the fire of 1871, as many structures were rebuilt at a rapid pace.

Step-by-step explanation: credit to beverlymichelle in the comments

6 0
3 years ago
Prove that sin3a-cos3a/sina+cosa=2sin2a-1
Sloan [31]

Answer:

\frac{sin(3a)-cos(3a)}{sin(a)+cos(a)} =2sin(2a)-1

Step-by-step explanation:

we are given

\frac{sin(3a)-cos(3a)}{sin(a)+cos(a)} =2sin(2a)-1

we can simplify left side and make it equal to right side

we can use trig identity

sin(3a)=3sin(a)-4sin^3(a)

cos(3a)=4cos^3(a)-3cos(a)

now, we can plug values

\frac{(3sin(a)-4sin^3(a))-(4cos^3(a)-3cos(a))}{sin(a)+cos(a)}

now, we can simplify

\frac{3sin(a)-4sin^3(a)-4cos^3(a)+3cos(a)}{sin(a)+cos(a)}

\frac{3sin(a)+3cos(a)-4sin^3(a)-4cos^3(a)}{sin(a)+cos(a)}

\frac{3(sin(a)+cos(a))-4(sin^3(a)+cos^3(a))}{sin(a)+cos(a)}

now, we can factor it

\frac{3(sin(a)+cos(a))-4(sin(a)+cos(a))(sin^2(a)+cos^2(a)-sin(a)cos(a)}{sin(a)+cos(a)}

\frac{(sin(a)+cos(a))[3-4(sin^2(a)+cos^2(a)-sin(a)cos(a)]}{sin(a)+cos(a)}

we can use trig identity

sin^2(a)+cos^2(a)=1

\frac{(sin(a)+cos(a))[3-4(1-sin(a)cos(a)]}{sin(a)+cos(a)}

we can cancel terms

=3-4(1-sin(a)cos(a))

now, we can simplify it further

=3-4+4sin(a)cos(a))

=-1+4sin(a)cos(a))

=4sin(a)cos(a)-1

=2\times 2sin(a)cos(a)-1

now, we can use trig identity

2sin(a)cos(a)=sin(2a)

we can replace it

=2sin(2a)-1

so,

\frac{sin(3a)-cos(3a)}{sin(a)+cos(a)} =2sin(2a)-1


7 0
3 years ago
Read 2 more answers
What is the correct answer?​
Nutka1998 [239]

Answer:

D) 8

Step-by-step explanation:

You multiply 10 by 12 to get 120 so you multiply x by 12 to get 96.

96 = 12x

/12     /12

8   =   x

5 0
3 years ago
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