Answer:
y=8x-67
Step-by-step explanation:
So the question is what is the equation for the following two coordinate points?
Well to start off what is the formula? The formula is called the linear equation. Which is y=mx+b. What does these letters or "variables" mean or represent?! Welp, m stands for the slope, which is "Δy over Δx." Some people call say "the change of y over x." I call it the rise over run. So it is saying y over x. The b in the linear equation is the y-intercept. The y-intercept is when the line crosses the y-axis.
With that being said, let's find the slope. But how? Well with the Δy over Δx. The formula is y₂-y₁ over x₂-x₁. With the two coordinate points we can label them.
y₂=5
y₁=(-11)
x₂=9
x₁= 7
Now let set it up into the equation of y over x
Slope = <u> 5- (-11) </u> = <u> 5 + 11 </u> = <u> 16 </u> = 8
9-7 9-7 2
So we now have the slope! Which is 8! So put that into the linear equation!
y=8x+b
Next, we need to find b, the y-intercept! How do we do that well, we can figure it out by one of the coordinate points! Let use the (7, -11) point for example! Remember, x= 7 and y= (-11)
(-11) = 8(7) + b
(-11) = 56 + b
<u>-56 -56</u>
-67 = b
We now have b, which is negative 67! So we need to put all the information we have found into the linear equation!
y=8x-67
Answer:
linear
Step-by-step explanation:
use Desmos can help A LOT
Answer:
(2x^3+4x^2-4x+6) / (x+3) = 2x^2-2x+2 => B
Step-by-step explanation:
Answer:
F' corresponds to point F
Step-by-step explanation:
When a point is the result of some transformation, we often designate that result using the base name of the original, with a prime (') added. In this case, we expect that F' is the transformation of point F.
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<em>Comment on point naming</em>
Of course, points can be given any name you like. These conventions are adopted to aid in communication about transformations and correspondence between points. It would be unusual--even confusing, but not unreasonable, for point F' to correspond to point D, for example. In the case of certain transformations, point F' may actually <em>be</em> point D.
