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iren [92.7K]
2 years ago
11

20 PTS QUICK QUICK PLEASE! 1 MINUTE ONLY! WITH EXPLANATION PLEASE! ANSWER 3 QUESTION AND YOU WILL BE THE BRAINLIEST!

Mathematics
1 answer:
Vesnalui [34]2 years ago
6 0

1) We want to find the area of the triangular bases, which means both shown in the net. So, normally we would divide the area by 2 (from the formula), but since we are finding the area of two triangles, that isn't necessary.

A = 8 x 3

2) There are two different sized rectangles here. One that is repeated twice and the other that is on its own. We know that A and C are the same, and if we think about how this net is folded, we can determine that the width of A and C would be 5 cm. For both sized rectangles, the length is 12 cm. For rectangle B, we can see that its width is 8 cm.

A = (8 x 12) + (5 x 12)

3) Now that we have all of the expressions needed to find the surface area, what we need to do is evaluate each of them and add them together to find the total surface area.

Triangles = 8 x 3 = 24

Rectangles = (8 x 12) + (5 x 12) = 96 + 60 = 156

Surface area = 24 + 156 = 180 square centimeters

Hope this helps! :)

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Correct question:

A food company sells salmon to various customers. The mean weight of the salmon is 44 lb with a standard deviation of 3 lbs. The company ships them to restaurants in boxes of 9 ​salmon, to grocery stores in cartons of 16 ​salmon, and to discount outlet stores in pallets of 64 salmon. To forecast​ costs, the shipping department needs to estimate the standard deviation of the mean weight of the salmon in each type of shipment. Complete parts​ (a) and​ (b) below.

a. Find the standard deviations of the mean weight of the salmon in each type of shipment.

b. The distribution of the salmon weights turns out to be skewed to the high end. Would the distribution of shipping weights be better characterized by a Normal model for the boxes or pallets?

Answer:

Given:

Mean, u = 44

Sd = 3

The company ships in boxes of 9, cartons of 16 and pallets of 64.

a) For the standard deviations of the mean weight of the salmon in each type of shipment, lets use the formula: \frac{s.d}{\sqrt{u}}

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\frac{s.d}{\sqrt{u}}

= \frac{3}{\sqrt{9}}

= \frac{3}{3} = 1

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ii) For the standard deviation of the mean weight of salmon in cartons of 16, we have:

\frac{s.d}{\sqrt{u}}

= \frac{3}{\sqrt{16}}

= \frac{3}{4} = 0.75

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iii) For the standard deviation of the mean weight of salmon in pellets of 64, we have:

\frac{s.d}{\sqrt{u}}

= \frac{3}{\sqrt{64}}

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Standard deviation = 0.375

b) The distribution of shipping weights would be better characterized by a Normal model for the pallets, because regardless of the underlying distribution, the sampling distribution of the mean approaches the Normal model as the sample increases.

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