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almond37 [142]
3 years ago
15

Order them from least to greatest

Mathematics
2 answers:
ella [17]3 years ago
7 0
8/3, 30/7, 40/9, 21/4
slega [8]3 years ago
5 0

Answer:

1. 8/3

2. 30/7

3. 40/9

4.21/4

Step-by-step explanation:

Don't worry about it

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Can someone help me I don't get it
Rina8888 [55]
The answer is 63 degrees.
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3 years ago
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<img src="https://tex.z-dn.net/?f=4x%20%7B%7D%5E%7B2%7D%20%20%2B%2020x%20%2B%2025" id="TexFormula1" title="4x {}^{2} + 20x + 25
BigorU [14]

\sf{\qquad\qquad\huge\underline{{\sf Answer}}}

Let's Solve ~

\qquad \sf  \dashrightarrow \: 4 {x}^{2}  + 20x + 25

\qquad \sf  \dashrightarrow \: 4 {x}^{2}  + 10x + 10x + 25

\qquad \sf  \dashrightarrow \: 2x(2x + 5) + 5(2x + 5)

\qquad \sf  \dashrightarrow \: (2x + 5) (2x + 5)

\qquad \sf  \dashrightarrow \: (2x + 5) {}^{2}

or

\sf{\qquad \sf  \dashrightarrow \: 4x² + 20x + 25 }

\sf{\qquad \sf  \dashrightarrow \: (2x)² + (2 \sdot 2x \sdot 5) + (5)²}

[ it's similar to expression - a² + 2ab + b² that is equal to (a + b)² ]

so, let's use this identity here to factorise :

\sf{\qquad \sf  \dashrightarrow \: (2x + 5)²}

I hope it was helpful ~

3 0
2 years ago
HELP ASAP! Please give a detailed explanation!
mash [69]

Answer:

If the first die is a 5, the second must be 5 or more in order to have a sum of at least ten.

Assuming it is a six sided die, the two values that would make this true are 5 and 6.

2 values/6 possible would be a probability of 2/6, which simplifies to 1/3

Final answer: 1/3

Step-by-step explanation:

6 0
3 years ago
PLEASE HELP I WILL MARK YOU AS BRAINLEST
denpristay [2]

Answer:

(i) Five number summary: Minimum value = 1, Q_1=18,Median=18.5, Q_3=20.5, Maximum value = 26.

(ii) IQR = 2.5, upper fence = 24.25 and lower fence = 14.25.

(iii) 26 is an outlier of the data.

Step-by-step explanation:

The given data set is

19, 18, 23, 18, 18, 26, 19, 16, 20, 18, 17, 21

Arrange the data set in ascending order.

16, 17, 18, 18, 18, 18, 19, 19, 20, 21, 23, 26

Divide the data set in 4 equal parts.

(16, 17, 18), (18, 18, 18), (19, 19, 20), (21, 23, 26)

Minimum value = 16

Q_1=\frac{18+18}{2}=18

Median=Q_2=\frac{18+19}{2}=18.5

Q_3=\frac{20+21}{2}=20.5

Maximum value = 26

The inter quartile range (IQR) of the data is

IQR=Q_3-Q_1=20.5-18=2.5

Upper fence :

Q_3+1.5(IQR)=20.5+1.5(2.5)=24.25

Lower fence :

Q_1-1.5(IQR)=18-1.5(2.5)=14.25

If the any element of the data set lies out side the upper fence and lower fence, then it is called an outlier.

26 ∉ [14.25, 24.25]

Therefore, 26 is an outlier of the data.

4 0
3 years ago
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Jody got 90 problems correct on her test. Mildred got 65% of that amount correct. How many did Mildred get correct?
NikAS [45]

Answer:

I think it is 59

Step-by-step explanation:

7 0
4 years ago
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