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4 years ago

Find the missing values assuming continuously compounded interest. (Round your answers to two decimal places.)

Mathematics

1 answer:

alexdok [17]4 years ago

4 0

Answer:

Step-by-step explanation:

Using the compound interest formula to calculate the amount compounded after 10years.

$A = P(1+r)^{nt}$

P = principal = $2000

r = rate (in %) = 5.6%

t = time (in years) = 10years

n = 1year = time used in compounding

$A = 2000(1+0.056)^{10} \\A = 2000(1.056)^{10}\\A = 2000*1.7244046\\A = 3448.81 (to\ 2dp)$

Amount compounded after 10 years is $3448.81

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Find the indicated probability or percentage for the sampling error. The distribution of weekly salaries at a large company is r

Flauer [41]

Answer:

The probability that the sampling error made in estimating the mean weekly salary for all employees of the company by the mean of a random sample of weekly salaries of 80 employees will be at most $75 is 0.9297.

Step-by-step explanation:

According to the Central Limit Theorem if we have a non-normal population with mean μ and standard deviation σ and appropriately huge random samples (n > 30) are selected from the population with replacement, then the distribution of the sample means will be approximately normally distributed.

Then, the mean of the distribution of sample means is given by,

$\mu_{\bar x}=\mu$

And the standard deviation of the distribution of sample means is given by,

$\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}$

The information provided is:

$\mu=\$1000\\\sigma=\$370\\n=80$

As n = 80 > 30, the central limit theorem can be used to approximate the sampling distribution of sample mean weekly salaries.

Let $\bar X$ represent the sample mean weekly salaries.

The distribution of $\bar X$ is: $\bar X\sim N(\$1000,\ \$41.37)$

Now we need to compute the probability of the sampling error made in estimating the mean weekly salary to be at most $75.

The sampling error is the the difference between the estimated value of the parameter and the actual value of the parameter, i.e. in this case the sampling error is, $|\bar X-\mu|= 75$ .

Compute the probability as follows:

$P(-75$

$=P(-1.81$

Thus, the probability that the sampling error made in estimating the mean weekly salary for all employees of the company by the mean of a random sample of weekly salaries of 80 employees will be at most $75 is 0.9297.

3 0

3 years ago

1. A baseball pitcher has pitched 12 2/3 innings.

bagirrra123 [75]

What is the rest of the question?

8 0

3 years ago

Is the answer to (-1)^2-(-2-(9-1)), 11?

yulyashka [42]

Answer: Yes that's correct

Work Shown:

(-1)^2-(-2-(9-1))

1-(-2-(8))

1-(-2-8)

1-(-10)

1 + 10

Note that (-1)^2 = (-1)*(-1) = 1, and subtracting a negative turns into a positive.

3 0

1 year ago

Find the greatest solution for x+y when x^2+y^2 = 7, x^3+y^3=10

damaskus [11]

Answer:

Step-by-step explanation:

set

$f(x,y)=x+y\\$

constrain:

$g(x,y)=x^2+y^2 = 7\\h(x,y)=x^3+y^3=10$

Partial derivatives:

$f_{x}=1\\f_{y} =1 \\g_{x}=2x \\g_{y}=2y\\h_{x}=3x^2 \\h_{y}=3y^2$

Lagrange multiplier:

$grad(f)=a*grad(g)+b*grad(h)\\$

$\left[\begin{array}{ccc}1\\1\end{array}\right]=a\left[\begin{array}{ccc}2x\\2y\end{array}\right]+b\left[\begin{array}{ccc}3x^2\\3y^2\end{array}\right]$

4 equations:

$1=2ax+3bx^2\\1=2ay+3by^2\\x^2+y^2=7\\x^3+y^3=10$

By solving:

$a=4/9\\b=-2/27\\x+y=4$

Second mathod:

Solve for x^2+y^2 = 7, x^3+y^3=10 first:

$x=\frac{1}{2} -\frac{\sqrt{13}}{2} \ or \ y=\frac{1}{2} +\frac{\sqrt{13}}{2} \\x=\frac{1}{2} +\frac{\sqrt{13}}{2} \ or \ y=\frac{1}{2} -\frac{\sqrt{13}}{2} \\x+y=-5\ or\ 1 \or\ 4$

The maximum is 4

6 0

3 years ago

Twice the difference of 3x and y increased by 5 times the sum of x and 2y

Phantasy [73]

The answer is 2(3x-y)+5(x+2y).

8 0

3 years ago