1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
FromTheMoon [43]
3 years ago
13

Find the missing values assuming continuously compounded interest. (Round your answers to two decimal places.)

Mathematics
1 answer:
alexdok [17]3 years ago
4 0

Answer:

<h2>$3448.81</h2>

Step-by-step explanation:

Using the compound interest formula to calculate the amount compounded after 10years.

A = P(1+r)^{nt}

P = principal  = $2000

r = rate (in %) = 5.6%

t = time (in years) = 10years

n = 1year = time used in compounding

A = 2000(1+0.056)^{10} \\A = 2000(1.056)^{10}\\A = 2000*1.7244046\\A = 3448.81 (to\  2dp)

Amount compounded after 10 years is $3448.81

You might be interested in
An economist uses the price of a gallon of milk as a measure of inflation. She finds that the average price is $3.82 per gallon
salantis [7]

Answer:

(a) The standard error of the mean in this experiment is $0.052.

(b) The probability that the sample mean is between $3.78 and $3.86 is 0.5587.

(c) The probability that the difference between the sample mean and the population mean is less than $0.01 is 0.5754.

(d) The likelihood that the sample mean is greater than $3.92 is 0.9726.

Step-by-step explanation:

According to the Central Limit Theorem if we have an unknown population with mean <em>μ</em> and standard deviation <em>σ</em> and appropriately huge random samples (<em>n</em> > 30) are selected from the population with replacement, then the distribution of the sample means will be approximately normally distributed.

Then, the mean of the distribution of sample mean is given by,

\mu_{\bar x}=\mu

And the standard deviation of the distribution of sample mean is given by,

\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}

The information provided is:

n=40\\\mu=\$3.82\\\sigma=\$0.33

As <em>n</em> = 40 > 30, the distribution of sample mean is \bar X\sim N(3.82,\ 0.052^{2}).

(a)

The standard error is the standard deviation of the sampling distribution of sample mean.

Compute the standard deviation of the sampling distribution of sample mean as follows:

\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}

    =\frac{0.33}{\sqrt{40}}\\\\=0.052178\\\\\approx 0.052

Thus, the standard error of the mean in this experiment is $0.052.

(b)

Compute the probability that the sample mean is between $3.78 and $3.86 as follows:

P(3.78

                               =P(-0.77

Thus, the probability that the sample mean is between $3.78 and $3.86 is 0.5587.

(c)

If the difference between the sample mean and the population mean is less than $0.01 then:

\bar X-\mu_{\bar x}

Compute the value of P(\bar X as follows:

P(\bar X

                    =P(Z

Thus, the probability that the difference between the sample mean and the population mean is less than $0.01 is 0.5754.

(d)

Compute the probability that the sample mean is greater than $3.92 as follows:

P(\bar X>3.92)=P(\frac{\bar X-\mu_{\bar x}}{\sigma_{\bar x}}>\frac{3.92-3.82}{0.052})

                    =P(Z

Thus, the likelihood that the sample mean is greater than $3.92 is 0.9726.

3 0
3 years ago
Dr. Manion a mixed 9.357G of chemical A, 12.082g of chemical b,
Gnoma [55]

Amount of chemical A mixed in medicine = 9.357 g

Amount of chemical B mixed in medicine = 12.082 g

Amount of chemical C mixed in medicine = 7.502 g

We have to determine the total amount of medicine he prepared in grams.

Total amount of medicine

= 9.357 + 12.082 + 7.502

= 28.941 grams

So, he prepared 28.941 grams of medicine.

Now, we have to round each chemical to the nearest tenth.

Amount of chemical A mixed in medicine = 9.357 g

Rounding to nearest tenth = 9.4 grams

Amount of chemical B mixed in medicine = 12.082 g

Rounding to nearest tenth = 12.1 grams

Amount of chemical C mixed in medicine = 7.502 g

Rounding to nearest tenth = 7.5 grams

6 0
3 years ago
A pyramid with a slant height 4.6 in whose triangular base measures 8 in on each side.Each altitude of the base measures of 6.9
kvasek [131]

Answer:

82.8 in²

Step-by-step explanation:

The surface area a triangular based pyramid :

Base area + 1/2(perimeter * slant height)

Base = 8 inches ; Slant height = 4.6 inches ; altitude of base measure = 6.9 inches

Base area of triangle :

1/2 * base * height

1/2 * 8 * 6.9

4 * 6.9

Base area = 27.6 in²

The perimeter, P = sum of sides ; (s1 + s2 + s3

P = 8 + 8 + 8 = 24 in

Hence,

Surface area = 27.6 in² + 1/2(24*4.6)

Surface area = 27.6 in² + (12 * 4.6) in²

Surface area = (27.6 + 55.2)

Surface area = 82.8 in²

6 0
3 years ago
10x+8=3(x-2) 10x+8=3x-6
d1i1m1o1n [39]

Answer:

x = -2

Step-by-step explanation:

10x+8=3x-6

subtract 10x-3x

7x+8= -6

subtract -6-8

7x=-14

divide 7 into -14

x = -2

Hope this helps!

4 0
3 years ago
Simplify a b c and d please help
Klio2033 [76]
A: -5/18
B:1 and 16/35
C: 7/30
D: 7/8
3 0
3 years ago
Other questions:
  • Adam and Nick are having an argument. Adam says if you have forty- five pencils to put into five boxes, you can use 45 ÷ 5 to fi
    14·1 answer
  • A computer salesperson's monthly income depends on the amount of his sales. his monthly income is a salary of $1575 plus 9% of h
    7·2 answers
  • Quotient to a Power Rule (4c^3/7b^4)^2 Enter the result.
    15·1 answer
  • Can i get some help on these 2 im confused
    10·1 answer
  • −5.2 + y = 7.5 which one please answer...
    13·2 answers
  • Which is closest to the volume of this circular cone?
    12·2 answers
  • Evaluate the expression below for s=2 and t=7
    11·1 answer
  • A line segment passes through the points (2,6) and
    9·1 answer
  • Suppose g(x)=f(x-3)-4. which statement best compares the graph of g(x) with the graph of f(x)
    6·1 answer
  • What is the slope of the line through (- 7 8 and 0 4?; What is the slope of the line that passes through the points − 1 − 7 − 1
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!