Answer:
55
Step-by-step explanation:
The three angles form a straight line, so they add to 180.
x + x + 70 = 180
Combine like terms
2x+70 =180
Subtract 70 from each side
2x+70-70 =180-70
2x= 110
Divide by 2
x = 55
SQT = x
So SQT = 55
Associative property and distributive property
So to find the answer you want to isolate the y. So the first thing you want to do is to move everything to the opposite side of the = sign. You start by adding 10 to both sides.
10+ 5y -10 = -25 +10
5y = -15.
the tens cancel out on the left side and on the right you get left with -15/
Since y is being multiplied by 5 you always want to do the opposite so you divide by 5.
5y/5 = -15/5
y = -3
It's hard to explain but you just have to remember that what you do to one side you must do to the other to keep the equation balanced.
Answer:
perimeter of the shaded region = 88 +44+28 =160 cm
Step-by-step explanation:
perimeter of shaded region = length AO + arc OB + arc AB
length AO = radius of bigger circle
radius of bigger circle = OX + OB = 2×radius of smaller circle = 2×14 cm = 28 cm
therefore AO = 28 cm
length of arc oB= half of circumference of smaller circle =
×14 = 44 cm
length of arc ab = half of circumference of bigger circle =
×28 =
×28= 88
therefore perimeter of the shaded region = 88 +44+28 =160 cm
area of the shaded region = half of area of bigger circle - half of area of smaller circle
=![\frac{1}{2} \pi 28^{2} -\frac{1}{2} \pi 14^{2}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%20%5Cpi%2028%5E%7B2%7D%20-%5Cfrac%7B1%7D%7B2%7D%20%5Cpi%2014%5E%7B2%7D)
=![\frac{\pi }{2} (28^{2} -14^{2} )](https://tex.z-dn.net/?f=%5Cfrac%7B%5Cpi%20%7D%7B2%7D%20%2828%5E%7B2%7D%20-14%5E%7B2%7D%20%29)
solving we gen area of shaded region = 924
Answer:
x = -3/2
Step-by-step explanation:
The removable discontinuity is at the value of x where a denominator factor cancels a numerator factor, and those factors are zero.
![p(x)=\dfrac{2x+3}{4x^2-9}=\dfrac{2x+3}{(2x+3)(2x-3)}=\dfrac{2x+3}{2x+3}\cdot\dfrac{1}{2x-3}\\\\p(x)=\dfrac{1}{2x-3}\qquad x\ne-3/2](https://tex.z-dn.net/?f=p%28x%29%3D%5Cdfrac%7B2x%2B3%7D%7B4x%5E2-9%7D%3D%5Cdfrac%7B2x%2B3%7D%7B%282x%2B3%29%282x-3%29%7D%3D%5Cdfrac%7B2x%2B3%7D%7B2x%2B3%7D%5Ccdot%5Cdfrac%7B1%7D%7B2x-3%7D%5C%5C%5C%5Cp%28x%29%3D%5Cdfrac%7B1%7D%7B2x-3%7D%5Cqquad%20x%5Cne-3%2F2)
That cancellation occurs where 2x+3 = 0, at x=-3/2.
The function p(x) has a removable discontinuity when x = -3/2.