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pantera1 [17]
3 years ago
12

HELPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP

Mathematics
1 answer:
Xelga [282]3 years ago
3 0

Answer:

2. 3/4.

3. Equal.

4. Not Equal.

5. Equal

6. Equal

7. Margaret and Steve

8. 2/3 & 6/9

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I need help fast thank you so much
valkas [14]

Answer:710

Step-by-step explanation:multiply 3000 by 3.3

3 0
3 years ago
Compute the multifactor productivity measure for each of the weeks shown for production of chocolate bars. What do the productiv
liq [111]

Answer:

Week 1 =3.03

Week 2 =2.99

Week 3=2.9

Week 4=2.83

Step-by-step explanation:

Computation for the multifactor productivity measure for each of the weeks shown for production of chocolate bars.

Using this formula

Week Multifactor productivity measure = (Output / Total Cost)

Where:

Output represent Quantity produced

Total cost represent Labor cost + Material cost + Overhead

Let plug in the formula

Week 1= 30,000/(40*12*6)+[(40*12*6)1.5]+(450*6)

Week 1 =30,000/(2,880)+(2,880*1.5)+2,700

Week 1 =30,000/(2,880+4,320+2,700)

Week 1=30,000/9,900

Week 1 =3.03

Week 2= 33,600/(40*12*7)+[(40*12*7)1.5]+(470*6)

Week 2 =33,600/(3,360)+(3,360*1.5)+2,820

Week 2=33,600/(3,360+5,040+2,820)

Week 2=33,600/11,220

Week 2 =2.99

Week 3= 32,200/(40*12*7)+[(40*12*7)1.5]+(460*6)

Week 3 =32,200/(3,360)+(3,360*1.5)+2,760

Week 3=32,200/(3,360+5,040+2,760)

Week 3=32,200/11,160

Week 3=2.9

Week 4= 35,400/(40*12*8)+[(40*12*8)1.5]+(480*6)

Week 4 =35,400/(3,840)+(3,840*1.5)+2,880

Week 4=35,400/(3,840+5,760+2,880)

Week 4=35,400/12,480

Week 4=2.83

Therefore the multifactor productivity measure for each of the weeks shown for production of chocolate bars is :

Week 1 =3.03

Week 2 =2.99

Week 3=2.9

Week 4=2.83

4 0
3 years ago
How do u do this? Help plz
aniked [119]
P=2250e^(rt)
P/2250=e^(rt)
ln(P/2250)=ln(e^(rt))
ln(P/2250)=rt
r=ln(P/2250)/t
6 0
4 years ago
Which of the following is an example of a quadratic equation
raketka [301]

Answer:

x

2

=36x, start superscript, 2, end superscript, equals, 36

(x-2)^2=49(x−2)

2

=49left parenthesis, x, minus, 2, right parenthesis, start superscript, 2, end superscript, equals, 49 [Why is this a quadratic equation?]

x^2

x, start superscript, 2, end superscript(x-2)^2

left parenthesis, x, minus, 2, right parenthesis, start superscript, 2, end superscriptxx

\begin{aligned}(x-2)^2&=49\\\\ x^2-4x+4&=49\end{aligned}

 

x^2

x, start superscript, 2, end superscript

2x^2+3=1312x

2

+3=131

Step-by-step explanation:

8 0
4 years ago
Select the equation where x = 6 is a solution.Immersive Reader (20 Points) 6x=66 5x=30 6x=1 7x+2=15
AlladinOne [14]

Answer:

5x=30

Step-by-step explanation:

if x equals 6, 5 times 6 must equal 30

3 0
3 years ago
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