All categories

3 years ago

HELPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP

Mathematics

1 answer:

Xelga [282]3 years ago

3 0

Answer:

2. 3/4.

3. Equal.

4. Not Equal.

5. Equal

6. Equal

7. Margaret and Steve

8. 2/3 & 6/9

You might be interested in

The reference angle for 305

zaharov [31]

Answer:

55°

Step-by-step explanation:

The angle 305° is in the fourth quadrant

To find the related acute angle ( the reference angle ) subtract from 360°

reference angle = 360° - 305° = 55°

5 0

3 years ago

Please help if you want points and happy ramadan if you celebrate it

umka2103 [35]

Answer:

1. yes

2.no

3.yes

4. no

hope this helps I'm not sure about number 2 tho

6 0

3 years ago

Read 2 more answers

There are 56 trees in a apple orchard. They are arranged in equal rows. There are 8 trees in each row. How many rows of apple tr

uysha [10]

Hello there.

Question: <span>There are 56 trees in a apple orchard. They are arranged in equal rows. There are 8 trees in each row. How many rows of apple trees are there? What's the equation can be used for this problem?

Answer: 56/8 = 7.
There are 7 rows.
The equation would be:
Let trees be t.
8t = 56.

Hope This Helps You!
Good Luck Studying ^-^</span>

8 0

3 years ago

Read 2 more answers

Find the value of 4th terms by using 3n-2

Serga [27]

10 is the answer I think

7 0

3 years ago

Read 2 more answers

How many weeks of data must be randomly sampled to estimate the mean weekly sales of a new line of athletic footwear? We want 98

Irina18 [472]

Answer:

$n=(\frac{2.33(1400)}{400})^2 =66.50 \approx 67$

So the answer for this case would be n=67 rounded up

Step-by-step explanation:

Information given

$\bar X$ represent the sample mean for the sample

$\mu$ population mean

$\sigma=1400$ represent the sample standard deviation

n represent the sample size

Solution to the problem

The margin of error is given by this formula:

$ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (a)

And on this case we have that ME =400 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=(\frac{z_{\alpha/2} \sigma}{ME})^2$ (b)

The critical value for 98% of confidence interval now can be founded using the normal distribution. And the critical value would be $z_{\alpha/2}=2.33$ , replacing into formula (b) we got:

$n=(\frac{2.33(1400)}{400})^2 =66.50 \approx 67$

So the answer for this case would be n=67 rounded up

8 0

4 years ago