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andriy [413]
3 years ago
5

Heights of adult women in the united states are normally distributed with a population mean of μ = 63.5 inches and a population

standard deviation of σ = 2.5. a medical researcher is planning to select a large random sample of adult women to participate in a future study. what is the standard value, or z-value, for an adult woman who has a height of 50.4 inches? (calculate to 1 decimal)
Mathematics
1 answer:
maw [93]3 years ago
3 0
Given:
<span>population mean of μ = 63.5 inches
population standard deviation of σ = 2.5 inches
</span><span>adult woman who has a height of 50.4 inches
</span>
<span>z = (x – μ) / σ

z = (50.4 - 63.5) / 2.5 = -13.1 / 2.5 = -5.24 

The z-value of an adult woman who has a height of 50.4 inches is -5.24 or -5.24 standard deviation below the mean. </span>
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Answer:

After 50 years the stock value will be $50 per share.

Step-by-step explanation:

Simple Interest Equation (Principal + Interest)

A = P(1 + rt)

Where:

A = Future amont = $50

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r = Rate of Interest per year in decimal; r = R/100 = 0.5/100 = 0.005

t = Time Period involved in months or years  

Plug in the values

50 = 40(1 + 0.005t)

50 / 40 = (1 + 0.005t)

5/4 = 1 + 0.005t

5/4 - 1 = 0.005t

0.25 = 0.005t

t = 0.25 / 0.005

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Step-by-step explanation:

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Answer:

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