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andriy [413]
4 years ago
5

Heights of adult women in the united states are normally distributed with a population mean of μ = 63.5 inches and a population

standard deviation of σ = 2.5. a medical researcher is planning to select a large random sample of adult women to participate in a future study. what is the standard value, or z-value, for an adult woman who has a height of 50.4 inches? (calculate to 1 decimal)
Mathematics
1 answer:
maw [93]4 years ago
3 0
Given:
<span>population mean of μ = 63.5 inches
population standard deviation of σ = 2.5 inches
</span><span>adult woman who has a height of 50.4 inches
</span>
<span>z = (x – μ) / σ

z = (50.4 - 63.5) / 2.5 = -13.1 / 2.5 = -5.24 

The z-value of an adult woman who has a height of 50.4 inches is -5.24 or -5.24 standard deviation below the mean. </span>
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Solve this system of linear equations. Separate the x- and y-values with a comma. -7x + 2y = -8 -16x + 9y = 26
Goryan [66]
(4,10). 
1. There are three ways to solve this: elimination, substitution, graphing.
2. I chose elimination, so I had to get one negative variable and one positive variable of the same value (for example, 18 and -18)

-7x+2y=-8
-16x+9y=26
I chose to get 2y and 9y to equal -18y and 18y. 
So, multiply the first equation by -9. Multiply the second by 2.
63x-18y=72
-32x+18y=52
the 18s cross each other out. So you're left with
63x=72
-32x=52. Add them. 
31x=124, divide both sides by 31, and you'll get 4. 
x=4
Plug your answer for x into one of the equations. Let's use the first one.
-7(4)+2y=-8
-28+2y=-8. add 28 to both sides.
2y=20, divide both sides by 2.
y=10. 
This makes your answer (4,10)
8 0
4 years ago
Write a polynomial function of minimum degree in standard form with real coefficients whose zeros and their multiplicities inclu
Softa [21]

<u>Answer-</u>

<em>The polynomial function is,</em>

y=x^4-10x^3+38x^2-64x+40

<u>Solution-</u>

The zeros of the polynomial are 2 and (3+i). Root 2 has multiplicity of 2 and (3+i) has multiplicity of 1

The general form of the equation will be,

\Rightarrow y=(x-(2))^2(x-(3+i))(x-(3-i))   ( ∵ (3-i) is the conjugate of (3+i) )

\Rightarrow y=(x-2)^2(x-3-i)(x-3+i)

\Rightarrow y=(x^2-4x+4)((x-3)-i)((x-3)+i)

\Rightarrow y=(x^2-4x+4)((x-3)^2-i^2)

\Rightarrow y=(x^2-4x+4)((x^2-6x+9)+1)

\Rightarrow y=(x^2-4x+4)(x^2-6x+10)

\Rightarrow y=x^2x^2-6x^2x+10x^2-4x^2x+4\cdot \:6xx-4\cdot \:10x+4x^2-4\cdot \:6x+4\cdot \:10

\Rightarrow y=x^4-10x^3+14x^2+24x^2-40x-24x+40

\Rightarrow y=x^4-10x^3+38x^2-64x+40

Therefore, this is the required polynomial function.


4 0
4 years ago
Determine which lines, if any, are parallel? Explain.
AfilCa [17]
I don’t even know at this point lol
3 0
3 years ago
Anna and Veronica are on the opposite sides of a tower of 160 meters height. They measure the angle of elevation of the top of t
MAXImum [283]

Answer: The distance between the girls is 362.8 meters.

Step-by-step explanation:

So we have two triangle rectangles that have a cathetus in common, with a length of 160 meters.

The adjacent angle to this cathetus is 40° for Anna, then the opposite cathetus (the distance between Anna and the tower) can be obtained with the relationship:

Tan(A) = opposite cath/adjacent cath.

Tan(40°) = X/160m

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Now, we can do the same thing for Veronica, but in this case the angle adjacent to the tower is 55°

So we have:

Tan(55°) = X/160m

Tan(55°)*160m = X = 228.5 m

And we know that the girls are in opposite sides of the tower, so the distance between the girls is equal to the sum of the distance between each girl and the tower, then the distance between the girls is:

Dist = 228.5m + 134.3m = 362.8m

8 0
3 years ago
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mr_godi [17]
Setup 2 problems
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Or you can write it  -4 < x < 11

7 0
3 years ago
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