Help due in 40 minutes please don’t know what to do

Mathematics

1 answer:

aalyn [17]3 years ago

3 0

Answer:

1) b

2) c

Step-by-step explanation:

$\mid a \mid =5$

a can be either 5 or -5, because the absolute value of those is both 5. Therefore, the correct answer for this is b.

$\mid a \mid=-5$

Since the absolute value function will always return a positive value, this equation must have no solutions, or choice C. Hope this helps!

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1 7/10 - 1 1/2 <br> it has to be a fraction and no links

Masteriza [31]

First you start solving each mixed fraction:
17/10 - 3/2
Now we have improper fractions; fractions that have a numerator larger than the denominator
Next we will find the common denominator using LCM but what I personally do is I multiply both sides by the opposite fraction’s denominator, like this:
17 x 2 _ 3 x 10 —-> 34 - 30
10 x 2 2 x 10 20 - 20

Now we have 34/20 - 30/20 and with the help of collecting the common denominator, all we have to do now is subtract 30 from 34, and our answer will be 4/20
**when we have the same number as our denominator we only add or subtract the numerator, depending on what question your teacher asks you to answer
*** sum = addition/adding
difference = subtraction/subtracting/taking away

8 0

3 years ago

Read 2 more answers

Larry and Paul start out running at a rate of 5 mph. Paul speeds up his pace after 5 miles to 10 mph but Larry continues the sam

klasskru [66]

<h2>Hello!</h2>

The answer is:

They will be 10 miles apart after 3 hours.

To calculate how long after they start will they be 10 miles apart, we need to assume that after 1 one hour, they were at the same distance (5 miles), then, calculate the time when they are 10 miles apart, knowing that Paul increased its speed two times, running first at 5mph and then, at 10 mph.

The time that will pass to be 10 miles apart can be calculated using the following equation:

$TotalTime=TimeToReach5miles+TimeToBe10milesApart$

Calculating the time to reach 5 miles for both Larry and Paul, at a speed of 5 mph, we have:

$x=xo+v*t\\\\5miles=0+5mph*t\\\\t=\frac{5miles}{5mph}=1hour$

We have that to reach a distance of 5 miles, they needed 1 hour. We need to remember that at this time, they were at the same distance.

If we want to know how many time will it take for them to be 10 miles apart with Paul increasing its speed to 10mph, we need to assume that after that time, the distance reached by Paul will be the distance reached by Larry plus 10 miles.

So, for the second moment (Paul increasing his speed) we have:

For Larry:

$x_{L}=5miles+5mph*t$

Therefore, the distance of Paul will be equal to the distance of Larry plus 10 miles.

For Paul:

$x{L}+10miles=xo+10mph*t\\\\5miles+5mph*t+10miles=5miles+10mph*t\\\\5miles+10miles-5miles=10mph*t-5mph*t\\\\10miles=5mph*t\\\\t=\frac{10miles}{5mph}=2hours$