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2 years ago

9

Hey can you please help me posted picture of question

2 answers:

puteri [66]2 years ago

5 0

We have the following function:
P (m) = m / 6 + 9
Clearing m we have:
m = 6 * (p-9)
m= 6*p - 6*9
Rewriting:
m (p) = 6p-54
Answer:
The inverse function for this case is given by:
m (p) = 6p-54
option A

Vlada [557]2 years ago

3 0

The correct answer is option B.

The solution is shown below

$P(m)= \frac{m}{6} -9 \\ \\ p=\frac{m}{6} -9 \\ \\ p+9=\frac{m}{6} \\ \\ 6(p+9)=m \\ \\ m=6p+54 \\ \\ M(p)=6p+54 \\ \\ M(p)=6m+54 \\ \\$

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Answer/Step-by-step explanation:

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2 years ago

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Step-by-step explanation:

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3 years ago

Read 2 more answers

Given <br><img src="https://tex.z-dn.net/?f=%20log_%7B2%7D%28x%29%20%20%3D%20%20%5Cfrac%7B3%7D%7B%20log_%7Bxy%7D%282%29%20%7D%20

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Answer:

$\displaystyle y = x^{-\frac{2}{3}}$

Step-by-step explanation:

<u>Logarithms</u>

Some properties of logarithms will be useful to solve this problem:

1. $\log(pq)=\log p+\log q$

2. $\displaystyle \log_pq=\frac{1}{\log_qp}$

3. $\displaystyle \log p^q=q\log p$

We are given the equation:

$\displaystyle \log_{2}(x) = \frac{3}{ \log_{xy}(2) }$

Applying the second property:

$\displaystyle \log_{xy}(2)=\frac{1}{ \log_{2}(xy)}$

Substituting:

$\displaystyle \log_{2}(x) = 3\log_{2}(xy)$

Applying the first property:

$\displaystyle \log_{2}(x) = 3(\log_{2}(x)+\log_{2}(y))$

Operating:

$\displaystyle \log_{2}(x) = 3\log_{2}(x)+3\log_{2}(y)$

Rearranging:

$\displaystyle \log_{2}(x) - 3\log_{2}(x)=3\log_{2}(y)$

Simplifying:

$\displaystyle -2\log_{2}(x) =3\log_{2}(y)$

Dividing by 3:

$\displaystyle \log_{2}(y)=\frac{-2\log_{2}(x)}{3}$

Applying the third property:

$\displaystyle \log_{2}(y)=\log_{2}\left(x^{-\frac{2}{3}}\right)$

Applying inverse logs:

$\boxed{y = x^{-\frac{2}{3}}}$

7 0

2 years ago