Suppose an isosceles triangle ABC has A = 45° and b = c = 4. What is the length of a2?
1 answer:
You can use the Law of Cosines (a^2=b^2+c^2-2bc cosA)
a^2=4^2+4^2-2*4*4*cos45°
a^2=32-32cos45°
a^2=32(1-cos45°)
a=√(32(1-cos45°))
a≈3.06 units (to nearest hundredth of a unit)
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