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Shalnov [3]
2 years ago
6

Suppose an isosceles triangle ABC has A = 45° and b = c = 4. What is the length of a2?

Mathematics
1 answer:
const2013 [10]2 years ago
4 0
You can use the Law of Cosines (a^2=b^2+c^2-2bc cosA)

a^2=4^2+4^2-2*4*4*cos45°

a^2=32-32cos45°

a^2=32(1-cos45°)

a=√(32(1-cos45°))

a≈3.06 units (to nearest hundredth of a unit)
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Select the quadratic equation that has no real solutions.
julsineya [31]

Answer: In the quadratic formula, if the discriminant is greater than or equal to 0, then the solutions to the quadratic equation will be real numbers. ... Looking at the graph of a quadratic equation, if the parabola does not cross or intersect the x-axis, then the equation has no real solution.

3 0
2 years ago
The variable z is directly proportional to x, and inversely proportional to y. When x is 6 and y is 6, z has the value 12.
dalvyx [7]

z is directly proportional to x: z = kx.

If z is directly proportional to x and inversely proportional to y, then z = Kx/y.

When x= 6 and y = 6, z is 12. Find the constant of proportionality, K:

12 = K(6/6), or K = 12

Then, in general, z = 12x/y.

What is z when x=13 and y=10? z = 12(13)/(10) = 15.6 (answer)

3 0
3 years ago
I need help please :(<br> The last one is 30,21,11
Shalnov [3]
It is b because it makes sense
3 0
3 years ago
The distance d (in feet) that it
Marta_Voda [28]

Answer:

40 mph

Step-by-step explanation:

To find the maximum speed at which the car can travel, as the distance it requires to stop is 168 feet, we just need to use the value of d = 168 in the equation, and then find the value of s:

168 = 0.05s^2 + 2.2s

0.05s^2 + 2.2s - 168 = 0

Using Bhaskara's formula: we have:

Delta = 2.2^2 + 4*0.05*168 = 38.44

sqrt(Delta) = 6.2

s1 = (-2.2 + 6.2)/0.1 = 40 mph

s2 = (-2.2 - 6.2)/0.1 = -84 mph (a negative value does not make sense as 's' is the speed of the car)

So the maximum speed of the car is 40 mph

3 0
3 years ago
The volume of a cylinder is given by the formula v= m'h. where r is the radius of the cylinder and h is the height.
Verdich [7]

Answer:

The Volume of cylinder is: \mathbf{Volume=2\pi x^3-5\pi x^2-24\pi x+63\pi }

Option B is correct option.

Step-by-step explanation:

We are given:

Volume of cylinder = h = 2x+7

Radius of cylinder = r = x-3

We need to find volume of cylinder

The formula used is: Volume=\pi r^2h

Putting values and finding volume

Volume=\pi r^2h\\Volume=\pi (x-3)^2(2x+7)\\Volume=\pi (x^2-6x+9)(2x+7)\\Volume=\pi (2x(x^2-6x+9)+7(x^2-6x+9))\\Volume=\pi (2x^3-12x^2+18x+7x^2-42x+63)\\Volume=\pi (2x^3-12x^2+7x^2-42x+18x+63)\\Volume=\pi (2x^3-5x^2-24x+63)\\Volume=2\pi x^3-5\pi x^2-24\pi x+63\pi \\

So, The Volume of cylinder is: \mathbf{Volume=2\pi x^3-5\pi x^2-24\pi x+63\pi }

Option B is correct option.

8 0
2 years ago
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