Divide the first equation by 2 and add the result to the second equation. This will eliminate x.
... (-4x -2y)/2 + (2x +4y) = (-12)/2 +(-12)
... 3y = -18 . . . . . collect terms
... y = -6 . . . . . . . divide by 3
Substitute this into either equation to find x. Let's use the second equation, where the coefficient of x is positive.
... 2x +4(-6) = -12
... 2x = 12 . . . . . . . . add 24
... x = 6 . . . . . . . . . . divide by 2
The solution is (x, y) = (6, -6).
He had to put $65 bc. he had to balance his account then added $25
To solve this you need to use the formula for Chord-Chord length. You need to know it, it is ab=cd. with this, we can plug numbers in.
a=30
b=x+1
c=2x-6
d=21
So our new equation is:
30(x+1)=21(2x-6)
30x+30=42x-126
156=12x
x=13
This isn't what the question is askign for though, it wants YZ
Which is A+B or 30+x+1 or 21+13=34.
YZ=34
