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3 years ago

URGENT!!

Mathematics

1 answer:

Nana76 [90]3 years ago

6 0

Answer:

x = 2.4

Step-by-step explanation:

Given expression as,

2x - 4y when y = 3x - 6

Now put y in the given expression

so, 2x - 4 (3x - 6) = 0

2x - 12x + 24 = 0

10x = 24

So, x = $\frac{24}{10}$

Hence, x = 2.4 Answer

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What is the distance between (-7, -2) and (13,-23)

Zolol [24]

Step-by-step explanation:

here,

x1=-7

x2=13

y1=-2

y2=-23

$\boxed{\blue{ distance=\sqrt{(y2-y1)^2+(x2-x2)^2} }}$ ⠀

= $\tt{\sqrt{(-23-(-2))^2+(13-(-7))^2}}$ ⠀

= $\tt{\sqrt{(-21)^2+(20)^2} }$ ⠀

= $\tt{\sqrt{ 441+400} }$ ⠀

= $\tt{\sqrt{841} }$ ⠀

= $\tt{ 29 }$ ⠀

So,

the distance between (-7, -2) and (13,-23)=29

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3 years ago

An equilateral triangle has an altitude of 45. Find the length of a side of the triangle.

sukhopar [10]

Answer:

See attachment.

If altitude = 45 then

side = 2 * height (or altitude) / square root of 3

side = 2 * 45 / 1.7320508076

side = 90 / 1.7320508076

side = 51.9615242271

Step-by-step explanation:

6 0

4 years ago

Simplify the algebraic expression 3xy+5x+2+3y+x+4

Elza [17]

Answer:

3xy+6x+3y+6

Step-by-step explanation:

You just need to combine like terms.

5x and x are like terms so you can add them to 6x.

2 and 4 are like terms so you can add them to 6

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4 years ago

The shaded region R in diagram below is enclosed by y-axis, y = x^2 - 1 and y = 3.

Lostsunrise [7]

Cross sections of the volume are washers or annuli with outer radii x(y) + 1, where

y = x(y) ² - 1 ==> x(y) = √(y + 1)

and inner radii 1. The distance between the outermost edge of each shell to the axis of revolution is then 1 + √(y + 1), and the distance between the innermost edge of R on the y-axis to the axis of revolution is 1.

For each value of y in the interval [-1, 3], the corresponding cross section has an area of

π (1 + √(y + 1))² - π (1)² = π (2√(y + 1) + y + 1)

Then the volume of the solid is the integral of this area over [-1, 3]:

$\displaystyle\int_{-1}^3\pi y\,\mathrm dy = \frac{\pi y^2}2\bigg|_{-1}^3 = \boxed{4\pi}$

$\displaystyle\int_{-1}^3 \pi\left(2\sqrt{y+1}+y+1\right)\,\mathrm dy = \pi\left(\frac43(y+1)^{3/2}+\frac{y^2}2+y\right)\bigg|_{-1}^3 = \boxed{\frac{56\pi}3}$

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3 years ago

Test for origin symmetry: y=x/(x^2+1)

Korolek [52]

$y=\dfrac{x}{x^2+1}\\\\ -y=-\dfrac{-x}{(-x)^2+1}\\ -y=\dfrac{x}{x^2+1}\\ y=-\dfrac{x}{x^2+1}$

$-\dfrac{x}{x^2+1}\not =\dfrac{x}{x^2+1}$ so it's not symmetrical about the origin.

6 0

3 years ago