Help please I'm not getting this at all. I'll send the whole picture
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It takes 4.3 seconds for the rocket to return to earth.
The equation is:
where -9.8m/sec² is the acceleration due to gravity, v₀ is the initial velocity, and h₀ is the initial height. We will go from the assumption that the rocket is launched from the ground, so h₀=0, and we are told that the initial velocity, v₀, is 42. This gives us:
We will use the quadratic formula to solve this. The quadratic formula is:
Plugging in our information we have:
x=0 is when the rocket is launched; x=4.3 is when the rocket lands.
The equation is:
where -9.8m/sec² is the acceleration due to gravity, v₀ is the initial velocity, and h₀ is the initial height. We will go from the assumption that the rocket is launched from the ground, so h₀=0, and we are told that the initial velocity, v₀, is 42. This gives us:
We will use the quadratic formula to solve this. The quadratic formula is:
Plugging in our information we have:
x=0 is when the rocket is launched; x=4.3 is when the rocket lands.
The diameter of a circle is 16 kilometers. Then the area of the circle is
<u>Solution:</u>
Given that , the diameter of a circle is 16 kilometers
We have to find the area of the circle .
Radius is half of diameter.
<em><u>The area of circle is given as:</u></em>
Hence, the area of the circle is 201.062