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3 years ago

Find an explicit formula for f(n).

Mathematics

1 answer:

soldi70 [24.7K]3 years ago

5 0

Answer:

f(n) = 2n - 2

Step-by-step explanation:

Given the recursive formula

f(n) = f(n - 1) + 2 with f(1) = 0, then

f(2) = f(1) + 2 = 0 + 2 = 2

f(3) = f(2) + 2 = 2 + 2 = 4

f(4) = f(3) + 2 = 4 + 2 = 6

The terms of the sequence are 0, 2, 4, 6, ....

These are the first 4 terms of an arithmetic sequence with explicit formula

f(n) = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Here d = 2 - 0 = 4 - 2 = 6 - 4 = 2 and a₁ = 0, thus

f(n) = 0 + 2(n - 1), that is

f(n) = 2n - 2 ← explicit formula

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3 years ago

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Step-by-step explanation:

Event A:

Probability that a student has a Visa card.

Event B:

Probability that the student has a MasterCard.

We have that:

$A = a + (A \cap B)$

In which a is the probability that a student has a Visa card but not a MasterCard and $A \cap B$ is the probability that a student has both these cards.

By the same logic, we have that:

$B = b + (A \cap B)$

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$A = 0.6, B = 0.3$

(a) Could it be the case that P(A ∩ B) = 0.5?

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4 years ago

A sample of 81 account balances of a credit company showed an average balance of $1,200 with a standard deviation of $126.

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Answer:

(a) Null Hypothesis, $H_0$ : $\mu$ = $1,150

Alternate Hypothesis, $H_A$ : $\mu$ $\neq$ $1,150

(b) The test statistic is 3.571.

(c) We conclude that the mean of all account balances is significantly different from $1,150.

Step-by-step explanation:

We are given that a sample of 81 account balances of a credit company showed an average balance of $1,200 with a standard deviation of $126.

We have test the hypothesis to determine whether the mean of all account balances is significantly different from $1,150.

Let $\mu$ = mean of all account balances

(a)So, Null Hypothesis, $H_0$ : $\mu$ = $1,150 {means that the mean of all account balances is equal to $1,150}

Alternate Hypothesis, $H_A$ : $\mu$ $\neq$ $1,150 {means that the mean of all account balances is significantly different from $1,150}

The test statistics that will be used here is One-sample t test statistics as we don't know about population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample average balance = $1,200

s = sample standard deviation = $126

n = sample of account balances = 81

(b) So, test statistics = $\frac{1,200-1,150}{\frac{126}{\sqrt{81} } }$ ~ $t_8_0$

= 3.571

The value of the sample test statistics is 3.571.

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Now, since P-value is less than the level of significance as 5% > 0.05%, so we sufficient evidence to reject our null hypothesis.

Therefore, we conclude that the mean of all account balances is significantly different from $1,150.

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3 years ago

Find an explicit formula for f(n). ​

Find an explicit formula for f(n).