Answer:
7.9
Step-by-step explanation:
The adjacent interior is 4
If we take the Pythagorean identity identity sin^2 x + cos^2 x = 1 then
<span>(cos^2 x + sin^2 x) / (cot^2 x - csc^2 x)
The numerator becomes 1 since addition order matters not.
1 / </span>(cot^2 x - csc^2 x)
If we factor the denominator out a negative
1 / -(<span>csc^2 x - cot^2 x)
Consider </span><span>sin^2 x + cos^2 x = 1. Divide both sides by sin^2 x to get
1 + cot^2 x = csc^2 x
Subtract both sides by cot^2 x to get 1 = csc^2 x - cot^2 x.
Replace the denominator
1 / -(1) = -1
For cos</span>^2 θ / sin^2 θ + csc θ sin θ, we use cscθ = 1/sinθ and cosθ/sinθ = cotθ so
= cos^2 θ / sin^2 θ + 1
= cot^2 θ + 1
We use 1 + cot^2 <span>θ = csc^2 </span>θ to simplify this to
= csc^2 θ
Answers: -1
csc^2 θ
20% of $19,400 is $3,880
($19,400 / 5 = $3,880)
subtract 20% from the original value
($19,400 - $3,880 = $15,520)
it's now worth $15,520
<span>The y-intercept of is .
Of course, it is 3 less than , the y-intercept of .
Subtracting 3 does not change either the regions where the graph is increasing and decreasing, or the end behavior. It just translates the graph 3 units down.
It does not matter is the function is odd or even.
is the mirror image of stretched along the y-direction.
The y-intercept, the value of for , is</span><span>which is times the y-intercept of .</span><span>Because of the negative factor/mirror-like graph, the intervals where increases are the intervals where decreases, and vice versa.
The end behavior is similarly reversed.
If then .
If then .
If then .
The same goes for the other end, as tends to .
All of the above applies equally to any function, polynomial or not, odd, even, or neither odd not even.
Of course, if polynomial functions are understood to have a non-zero degree, never happens for a polynomial function.</span><span> </span>
