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4 years ago

-16 - (-t) = -45 how do you solve this please help

Mathematics

2 answers:

zzz [600]4 years ago

8 0

Answer:

- 29

Step-by-step explanation:

Step 1:

- 16 - ( - t ) = - 45 Equation

Step 2:

- 16 + t = - 45 Open Parenthises

Step 3:

t = - 45 + 16 Add 16 on both siddes

Answer:

t = - 29

Hope This Helps :)

Arlecino [84]4 years ago

4 0

Answer:

t = -29

Step-by-step explanation:

Step 1: Write equation

-16 - (-t) = -45

Step 2: Solve for <em>t</em>

Simplify: -16 + t = -45
Add 16 to both sides: t = -29

Step 3: Check

<em>Plug in t to verify it's a solution.</em>

-16 - (-(-29)) = -45

-16 - 29 = -45

-45 = -45

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$\left(\begin{array}{c|cc}&$Running&$Down\\---&---&---\\$Running&0.90&0.10\\$Down&0.30&0.70\end{array}\right)$

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$P^1=\left(\begin{array}{c|cc}&$Running&$Down\\---&---&---\\$Running&0.90&0.10\\$Down&0.30&0.70\end{array}\right)$

$P^2=\begin{pmatrix}0.84&0.16\\ 0.48&0.52\end{pmatrix}$

If the system is initially running, the probability of the system being down in the next hour of operation is the $(a_{12})th$ entry of the P^2$ matrix.$

The probability of the system being down in the next hour of operation = 0.16

(b)After two(periods) hours, the transition matrix is:

$P^3=\begin{pmatrix}0.804&0.196\\ 0.588&0.412\end{pmatrix}$

Therefore, the probability that a system initially in the down-state is running

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(c)The steady-state probability of a Markov Chain is a matrix S such that SP=S.

Since we have two states, $S=[s_1$ s_2]$

$[s_1$ s_2]\left(\begin{array}{ccc}0.90&0.10\\0.30&0.70\end{array}\right)=[s_1$ s_2]$

Using a calculator to raise matrix P to large numbers, we find that the value of $P^k$ approaches [0.75 0.25]:

Furthermore,

$[0.75$ 0.25]\left(\begin{array}{ccc}0.90&0.10\\0.30&0.70\end{array}\right)=[0.75$ 0.25]$

The steady-state probabilities of the system being in the running state and in the down-state is therefore:

$[s_1$ s_2]=[0.75$ 0.25]$

4 0

4 years ago

-16 - (-t) = -45 how do you solve this please help​

-16 - (-t) = -45 how do you solve this please help