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Scorpion4ik [409]

3 years ago

11

The figure shown is an equilateral triangle. Calculate the length of each side and give your answer in cm.

1 answer:

cricket20 [7]3 years ago

4 0

Given at you have an equilateral triangle, all sides have the same length.

Therefore,
First side 2x-7 = Second side x+y-9 = Third side y+5

Let us look at the second and third sides for now:
x+y-9 = y+5
x = y+5 - (y-9)
x = y-y+5+9
x = 14

Then we look at equating the first and third sides:
2x-7 = y+5
y = 2x-7-5

Substitute x =14 in the equation above:
y = 2(14)-7-5
= 28-7-5
= 21-5
= 16

The length of the third side is:
y+5 = 16 +5 = 21

Given that the length of each sides are the same in an equilateral triangle, all sides have the length 21cm.

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there’s 13 snakes 11 lizards 7 turtles 8 tortoises how many fewer turtles and tortoises than snakes and lizard

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3 years ago

The number of typing errors made by a typist has a Poisson distribution with an average of three errors per page. If more than t

damaskus [11]

Answer:

0.6472 = 64.72% probability that a randomly selected page does not need to be retyped.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given interval.

Poisson distribution with an average of three errors per page

This means that $\mu = 3$

What is the probability that a randomly selected page does not need to be retyped?

Probability of at most 3 errors, so:

$P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)$

In which

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-3}*3^{0}}{(0)!} = 0.0498$

$P(X = 1) = \frac{e^{-3}*3^{1}}{(1)!} = 0.1494$

$P(X = 2) = \frac{e^{-3}*3^{2}}{(2)!} = 0.2240$

$P(X = 3) = \frac{e^{-3}*3^{3}}{(3)!} = 0.2240$

Then

$P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.0498 + 0.1494 + 0.2240 + 0.2240 = 0.6472$

0.6472 = 64.72% probability that a randomly selected page does not need to be retyped.

3 0

3 years ago