The length and width of the toolbox given the diagonal is 45 inches and 15 inches respectively.
<h3>Triangle</h3>
- Width of the triangle = w
- Length of the triangle = 3w
- Diagonal = 30 inches
Hypotenuse ² = opposite ² + adjacent ²
30² = w² + (3w²)
30² = 4w²
900 = 4w²
w² = 900/4
= 225
w = √225
w = 15
Therefore,
Width of the triangle = w
= 15 inches
Length of the triangle = 3w
= 3(15)
= 45 inches
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Answer:
-5x+5
Step-by-step explanation:
i just got this question
The overall length is given as 22.
The line is split into 2 parts X and 3X.
So we have X + 3X = 22
Add X and #X to get 4X:
4X = 22
Divide both sides by 4 to get X:
X = 22 /4
X = 5.5
Now we know what X is so now replace x with 5.5 and solve for LM:
LM = 3X = 3*5.5 = 16.5
Answer:can't see no 1
Step-by-step explanation:
2=A
3=c
Answer and Explanation:
Number of classes = 8
Highest value =2300
Lowest value = 1250
Class width= highest value – lowest value / number of classes
= 2300 – 1250/8
= 131.25 = 132
So, we can write class as 1250+132=1382
Class frequency
1250-1382 2
1382-1514 3
1514-1646 6
1646-1778 2
1778-1910 3
1910-2042 2
2042-2174 1
2174-2306 1
