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3 years ago

13

Carly is buying deli meat for her lunches this week. Turkey is on sale for $5.80 per pound. If Carly buys 1.25 pounds of turkey,

how much money does she spend?

2 answers:

alisha [4.7K]3 years ago

8 0

Answer:

Carly will have to spend $7.25

Step-by-step explanation:

We know that:

1 pound of turkey = $5.80

To find how much 1.25 pounds of turkey will cost, multiply:

5.80 x 1.25 = 7.25

Therefore, 1.25 pounds of turkey will cost $7.25

I really hope this helps!

-SpaceMarsh

kati45 [8]3 years ago

5 0

6.03 i believe , she gets one pound which equals to 5.80 and .25 more if you divide 5.80 with .25 you get .23 adding 5.80 with .23 equals $6.03

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Answer:

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4300( 4308.08)

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marlee spins a spinner and rolls 1-6 # cube. the spinner has 5 equal parts # 1-5 . what is the probability she will spin an even

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4 years ago

A simple random sample of size nequals81 is obtained from a population with mu equals 83 and sigma equals 27. (a) Describe the

Ivanshal [37]

Answer:

a) $\bar X \sim N (\mu, \frac{\sigma}{\sqrt{n}})$

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b) $z= \frac{89-83}{\frac{27}{\sqrt{81}}}= 2$

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Step-by-step explanation:

For this case we know the following propoertis for the random variable X

$\mu = 83, \sigma = 27$

We select a sample size of n = 81

Part a

Since the sample size is large enough we can use the central limit distribution and the distribution for the sampel mean on this case would be:

$\bar X \sim N (\mu, \frac{\sigma}{\sqrt{n}})$

With:

$\mu_{\bar X}= 83$

$\sigma_{\bar X}=\frac{27}{\sqrt{81}}= 3$

Part b

We want this probability:

$P(\bar X>89)$

We can use the z score formula given by:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And if we find the z score for 89 we got:

$z= \frac{89-83}{\frac{27}{\sqrt{81}}}= 2$

$P(Z>2) = 1-P(Z$

Part c

$P(\bar X$

We can use the z score formula given by:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And if we find the z score for 75.65 we got:

$z= \frac{75.65-83}{\frac{27}{\sqrt{81}}}= -2.45$

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Part d

We want this probability:

$P(79.4 < \bar X < 89.3)$

We find the z scores:

$z= \frac{89.3-83}{\frac{27}{\sqrt{81}}}= 2.1$

$z= \frac{79.4-83}{\frac{27}{\sqrt{81}}}= -1.2$

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