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PtichkaEL [24]
3 years ago
15

WHAT IS THISDSSSSSSSSSSSSSSSSSSS

Mathematics
1 answer:
MaRussiya [10]3 years ago
8 0

Answer:

B

Step-by-step explanation:

Yes, it is. The set of rational numbers is closed for all the four operations, so x+y, x-y, x*y and x/y are rational too. And it is easy to demonstrate. A rational number can be expressed as a fraction of two integers. So, x can be expressed as a/b and y as c/d. Hence x+y = a/b + c/d = (ad+bc)/bd, which, as fraction of two integers, is rational.

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Factor the following polynomial completely. Start by getting the GCF of the polynomial. 2x^3-18x
Vesna [10]

Answer:

GCF: 2x

Factored: 2x(x+3)(x-3)

Step-by-step explanation:

6 0
3 years ago
On a coordinate plane, 2 right triangles are shown. The first triangle has points A (negative 1, 3), B (negative 1, 1), C (3, 1)
drek231 [11]

Answer:

  • B and E

Step-by-step explanation:

<u>Given</u>

  • ΔABC ⇒ A(- 1, 3), B(- 1, 1), C(3, 1)
  • ΔA'B'C' ⇒ A'(2, - 2), B'(2, - 4), C'(6, - 4)

<u>Comparing the coordinates of the corresponding vertices, we see the difference:</u>

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It means the ΔABC has been translated 3 units right and 5 units down

Correct answer choices are B and E

8 0
2 years ago
Read 2 more answers
Find the Ratio of 250m to 1.5km
mestny [16]

Answer:

Step-by-step explanation:

1 km= 1000m

1.5 km = 1 x 1000 + 500

1000 + 500

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1500 m : 250 m

750 m : 125 m

150 m : 25 m

30 m : 5 m

6 m : 1m

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7 0
3 years ago
Read 2 more answers
I need help. Find the value of each variable.
azamat

Answer:

x=8, y=4\sqrt{3}

Look up the 30-60-90 triangle rule

8 0
2 years ago
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How do I find the slope of the line through (–9, –10) and (–2, –5)?
storchak [24]
Answer:
slope of line is 5/7

Explanation:
The slope of the line can be calculated using the following rule:
slope = \frac{y2-y1}{x2-x1}

The given points are:
(-9,-10) which represent (x1,y1)
(-2,-5) which represent (x2,y2)

Substitute with the points in the above equation to get the slope as follows:
slope = \frac{-5-(-10)}{-2-(-9)} = 5/7

Hope this helps :)

4 0
3 years ago
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