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Kipish [7]
2 years ago
6

Question 3 (Essay Worth 10 points)

Mathematics
2 answers:
atroni [7]2 years ago
6 0
1. Distribute the 6 to the 2x and the -11
12x-22+15=3x+12
2. Combine like terms
12x-7=3x+12
9x=+19
x=19/9
Part B x=19/9

ozzi2 years ago
5 0

Answer:

x=7

Step-by-step explanation:

sorry for bad hand writing

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user100 [1]
Flip a coin twenty five times, the purpose of this is to show that theoretical and experimental do not always overlap.

Theoretically, it should be a fifty-fifty chance.

In the experiment because you do it a odd amount of times, 25, each flip will be worth a four percent chance.

You would not be able to make a fifty fifty chance with that amount of flips.

Also here:

1.) 13 Heads, 12 tails

2.) 48% chance for the coin to land on tails, 52% chance for the coin to land on heads.

3.) The theoretical probability of a coin landing on heads is 50% of the time that the coin is flipped. This is because there are two possibilities with an equal likelihood of happening 

4) The theoretical probability and experimental probability are different as theoretically there would be an equal likelihood or probability and in the experiement, there was a higher probability for the coin to land on heads. 

5 0
2 years ago
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In a 30-60-90 right triangle, the shorter leg has a length of 4. What is the length of the longer leg? How would I figure this o
iVinArrow [24]

Answer:

use a^2 +b^2=c^2

Step-by-step explanation:


5 0
2 years ago
Helppp me please will give brainliest ​
iVinArrow [24]

Answer:

y=-2x+11

Step-by-step explanation:

5 0
2 years ago
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A prime number has two factors, itself and 1? *
slamgirl [31]

Answer:

That is true. More information below.

Step-by-step explanation:

A prime number has to have only two factors: 1 and itself. 1 only has one factor (itself) so it is, as you were saying, neutral.

6 0
2 years ago
Find the solution to this system of equations <br> 3x+2y+3z=3 4x-5y+7z=1 2x+3y-2z=6 <br> x=? Y=? Z=?
Ede4ka [16]

Answer:

The solution is x=2,\ y=0,\ z=-1.

Step-by-step explanation:

You are given the system of three equations:

\left\{\begin{array}{l}3x+2y+3z=3\\4x-5y+7z=1\\2x+3y-2z=6\end{array}\right.

Multiply the first equation by 4, the second equation by 3 and subtract them. Then multiply the third equation by 2 and subtract it from the second equation:

\left\{\begin{array}{l}3x+2y+3z=3\\4(3x+2y+3z)-3(4x-5y+7z)=4\cdot 3-3\cdot 1\\4x-5y+7z-2(2x+3y-2z)=1-2\cdot 6\end{array}\right.\Rightarrow \\\\\left\{\begin{array}{l}3x+2y+3z=3\\12x+8y+12z-12x+15y-21z=12-3\\4x-5y+7z-4x-6y+4z=1-12\end{array}\right.

So,

\left\{\begin{array}{rl}3x+2y+3z=3\\23y-9z=9\\-11y+11z=-11\end{array}\right.\Rightarrow \left\{\begin{array}{l}3x+2y+3z=3\\23y-9z=9\\y-z=1\end{array}\right.

Multiply the third equation by 23 and subtract it from the second equation:

\left\{\begin{array}{rl}3x+2y+3z=3\\23y-9z=9\\23y-9z-23(y-z)=9-23\cdot 1\end{array}\right.\Rightarrow \left\{\begin{array}{rl}3x+2y+3z=3\\23y-9z=9\\23y-9z-23y+23z=9-23 \end{array}\right.

Hence,

\left\{\begin{array}{rl}3x+2y+3z=3\\23y-9z=9\\14z=-14 \end{array}\right.\Rightarrow z=-1

Substitute it into the second equation:

23y-9\cdot (-1)=9\Rightarrow 23y+9=9\\ \\23y=0\\ \\y=0

Substitute them into the first equation:

3x+2\cdot 0+3\cdot (-1)=3\Rightarrow 3x-3=3\\ \\3x=6\\ \\x=2

The solution is x=2,\ y=0,\ z=-1.

3 0
3 years ago
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