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prisoha [69]
3 years ago
10

Help please ............ solveSolve X-3y=z-x+2y=-3

Mathematics
1 answer:
Alenkasestr [34]3 years ago
8 0
You don't need 3 equations to get a general solution.  To do this use the equations x-3y-z=0 and -x+2y+0z= -3.  Start out by letting z = t.  Then solving those 2 equations simultaneously, your x's cancel out leaving you with -y-z=-3.  But since z=t, then -y=-3+t or y=3-t.  Now sub that in for y in the first equation, along with the fact that z=t to get x-3(3-t)-t = 0 and solve for x. x=9-2t.  So a general solution for this would be (9-2t, 3-t, t)
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Step-by-step explanation:

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The 't' test statistic = 1.46 < 1.69

The test of hypothesis is H 0 :μ = 800 is accepted

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Step-by-step explanation:

Step 1:-

Given population of mean μ = 800

given size of small sample n =30

sample standard deviation 'S' = 45

Mean value of the sample χ = 788

Null hypothesis H_{0} =µ  =800

alternative hypothesis  H_{1} = µ ≠ 800

<u>Step 2</u>:-

The 't' test statistic t =  \frac{x-μ}{\frac{sig}{\sqrt{n} } }

                             t = \frac{788-800}{\frac{45}{\sqrt{30} } }

                       t = \frac{12}{8.215} = 1.4607

<u>Step 3</u>:-

The degrees of freedom γ = n-1 = 30-1 =29

From "t" value from table at 0.05 level of significance ( t = 1.69)

The calculated value t = 1.4607 < 1.69

Therefore The null hypothesis H_{0} ' is accepted.

<u>conclusion</u>:-

A sample of 30 bulbs are came found from average µ= 800

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