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3 years ago

I have this problem and I don’t know 287*6=25 what if the answer

Mathematics

1 answer:

Arte-miy333 [17]3 years ago

5 0

287•6 actually equals 1722... i dont know if this helps

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A glacier in Alaska moves about 29.99 a day about how much further will a move in a thousand days and it will move in a hundred

Lelu [443]

Try this: (29.99 units/day)(1000 days) = 29990 units.

Could you possibly include the given units of measurement in this post?

5 0

2 years ago

Colin received a bonus check for 2,500$. He is going to deposit the money into his bank account that receives 5.5% simple intere

alex41 [277]

This is the concept of financial mathematics, the simple interest rate is given by:
S.I.=(PRT)/100
where:
P=principle=$2500
R=rate=5.5%
T=time=1 year
Hence;
S.I.=(5.5*2500.1)/100
=$137.5
Thus the total amount he had after 1 year will be:
2500+137.5
=$2,637.5

6 0

2 years ago

A flower shop sells daffodils in bunches of 9 daffodils. The shop sells 27 daffodils. How many bunches of daffodils did the shop

amm1812

Answer:

its 3 brother

Step-by-step explanation:

you divide 27 by 9 and thats 3

6 0

2 years ago

An article in Fire Technology investigated two different foam-expanding agents that can be used in the nozzles of firefighting s

UNO [17]

Answer:

Step-by-step explanation:

Hello!

The objective of this experiment is to test if two different foam-expanding agents have the same foam expansion capacity

Sample 1 (aqueous film forming foam)

n₁= 5

X[bar]₁= 4.7

S₁= 0.6

Sample 2 (alcohol-type concentrates )

n₂= 5

X[bar]₂= 6.8

S₂= 0.8

Both variables have a normal distribution and σ₁²= σ₂²= σ²= ?

The statistic to use to make the estimation and the hypothesis test is the t-statistic for independent samples.:

t= $\frac{(X[bar]_1 - X[bar]_2) - (mu_1 - mu_2)}{Sa*\sqrt{\frac{1}{n_1} + \frac{1}{n_2 } } }$

a) 95% CI

(X[bar]_1 - X[bar]_2) ± $t_{n_1 + n_2 - 2}$ * $Sa* \sqrt{\frac{1}{n_1}+\frac{1}{n_2} }$

Sa²= $\frac{(n_1-1)S_1^2 + (n_2-1)S_2^2}{n_1 + n_2 - 2}$ = $\frac{(5-1)0.36 + (5-1)0.64}{5 + 5 - 2}$ = 0.5

Sa= 0.707ç

$t_{n_1 + n_2 -2: 1 - \alpha /2} = t_{8; 0.975} = 2.306$

(4.7-6.9) ± 2.306* $(0.707\sqrt{\frac{1}{5}+\frac{1}{5} })$

[-4.78; 0.38]

With a 95% confidence level you expect that the interval [-4.78; 0.38] will contain the population mean of the expansion capacity of both agents.

The hypothesis is:

H₀: μ₁ - μ₂= 0

H₁: μ₁ - μ₂≠ 0

α: 0.05

The interval contains the cero, so the decision is to reject the null hypothesis.

<u>Complete question</u>

a. Find a 95% confidence interval on the difference in mean foam expansion of these two agents.

b. Based on the confidence interval, is there evidence to support the claim that there is no difference in mean foam expansion of these two agents?

8 0

3 years ago

There are 1073 students at Raine High School. 26 percent do not identify as male or female, 42 percent identify as female, and 3

irinina [24]

Don’t Identify- 278.98
Female- 450.66
Male- 343.36

Considering these are people, you probably will need to round either up or down. If you round it would be:

Don’t Identify- 279
Female- 451
Male- 343

3 0

2 years ago