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Ilya [14]
3 years ago
10

How do you uninstall a program using the Control Panel?

Computers and Technology
1 answer:
igomit [66]3 years ago
7 0

Answer:

Option 4: Go to the Programs section, click Uninstall or change a program, highlight the program name, then click Uninstall.

Explanation:

  • There are many reasons to uninstall a program including need of extra space or removing unwanted Software.
  • Deleting a specific program is different from uninstalling it.
  • So in order to uninstall a program we go to control panel.
  • Click on the tab naming Programs and Features.
  • Find the option Uninstall or change a program.
  • Now locate the name of a program you want to uninstall and click it. two options will be their:
  1. Uninstall
  2. Repair
  • Click on the Uninstall option to complete the task.

I hope it will help you!

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Is C++ a high-level or low-level programming language? What about HTML?
N76 [4]

Answer:

c++ is low level

html high level

Explanation:

6 0
2 years ago
Write a C program to prform simple C aritlimetic calculations. The user is to enter a simple expression(integer operaior integer
larisa86 [58]

Answer:

Here is the C program:

#include <stdio.h>  //to use input output functions

//functions prototype

unsigned int mod(unsigned int a, unsigned int b);  

unsigned int mul(unsigned int a, unsigned int b);  

unsigned int sub( unsigned int a,unsigned int b);

float divide(unsigned int a,unsigned int b);  

unsigned int add( unsigned int a,unsigned int b);  

int main()  {  //start of main method

unsigned int a, b;   //declare variables to store the operands

char d;  //declare variable to store the operator

printf("Enter an operator:  ");   //prompts user to enter an operator

scanf("%c",&d);  //reads the operator from use

getchar();  //gets a character

while (d!='q')   { //keeps iterating until user enters q to quit

printf("Enter 1st operand: ");   //prompts user to enter first operand

scanf("%d",&a);   //reads first operand from user

getchar();  //reads character

printf("Enter 2nd operand: ");   //prompts user to enter second operand

scanf("%d",&b);   //reads second operand from user

getchar();  

if (d=='%')  {   //if the character of operator is a mod

printf("%d",a);  //prints operand 1

putchar(d);  //displays operator

printf("%d",b);  //displays operand 2

printf(" = ");  //displays =

mod(a,b);  }  //displays computed modulo of two input operands

if (d=='*')   //if the input character is for multiplication operator

{printf("%d",a);  //prints operand 1

putchar(d);  //displays operator

printf("%d",b);  //displays operand 2

printf(" = ");  //displays =

mul(a,b); }  //displays computed multiplication

if (d=='+')  {  //if the input character is for addition operator

printf("%d",a);  //prints operand 1

putchar(d);  //displays operator

printf("%d",b);  //displays operand 2

printf(" = "); // displays =

add(a,b);  }   //displays computed addition

if (d=='/')  {  //if the input character is for division operator

printf("%d",a); // prints operand 1

putchar(d);  //displays operator

printf("%d",b);  //displays operand 2

printf(" = ");  //displays =

divide(a,b);  }   //displays computed division

if (d=='-')  {  //if the input character is for subtraction operator

printf("%d",a);  //prints operand 1

putchar(d);  //displays operator

printf("%d",b); // displays operand 2

printf(" = ");  //displays =

sub(a,b);  }  //displays computed subtraction

printf("Enter an operator: ");   //asks again to enter an operator

scanf("%c",&d);  //reads operator from user

getchar();  }  }   //gets character

unsigned int mod( unsigned int a, unsigned int b){  //function to compute modulo of two integers with no sign

     int c = a%b;  //computes mod

    printf("%d",c);  }  //displays mod result

unsigned int add(unsigned int a, unsigned int b){     // function to compute addition of two integers

    int c = a+b; //computes addition

    printf("%d\n",c);  } //displays result of addition

unsigned int mul(unsigned int a, unsigned int b){       //function to compute multiplication of two integers

    int c = a*b;  //multiplies two integers

   printf("%d\n",c); }  //displays result of multiplication

float divide(unsigned int a, unsigned int b){   //function to compute division of two integers

    float c = a/b;  //divides two integers and stores result in floating point variable c

    printf("%f\n",c);  } //displays result of division

unsigned int sub(unsigned int a, unsigned int b){       //function to compute subtraction of two integers

    int c = a-b;  //subtracts two integers

    printf("%d\n",c);  }  //displays result of subtraction

Explanation:

The program is well explained in the comments mentioned with each line of the program. The program uses while loop that keeps asking user to select an operator and two operands to perform arithmetic calculations. The if conditions are used to check what arithmetic calculation is to be performed based on user choice of operand and calls the relevant function to perform calculation. There are five functions that perform addition, modulo, subtraction, division and multiplication and display the result of computation. The screenshot of output is attached.

4 0
3 years ago
Andrew has invested in a new CAD system to use in his workshop. What changes have occurred because he adopted the new system?
Bad White [126]

Answer:

B.   CAD produces designs that are of the highest quality.

C.   CAD provides systems for error-free manufacturing.

Explanation:

B.   CAD produces designs that are of the highest quality.

CAD does produce the highest quality of design, way better than what traditional paper plans can do.

C.   CAD provides systems for error-free manufacturing.

Many manufacturing systems can read CAD designs directly before the need of a human intervention in between, that eliminates possible errors.

Answers A and D are not true, because once passed the learning-curve, CAD greatly accelerates the production of designs.  And we know the learning-curve is behind them because the question says he has adopted the new system.

5 0
2 years ago
Read 2 more answers
Write a loop that sets each vector element to the sum of itself and the next element, except for the last element which stays th
Gekata [30.6K]

Answer:

Add the following lines of code to the already existing code segment

<em>for (i = 0; i < SCORES_SIZE-1; ++i) { </em>

<em>        bonusScores.at(i) = bonusScores.at(i) + bonusScores.at(i+1);</em>

<em>  }</em>

Explanation:

To do the task in the question, we have to iterate through the vector from the first element i.e. element at index 0 to the second to the last element; i.e. element at last index - 1

We then add each element in this iteration with the next.

This iterates through the vector from 0 to SCORES_SIZE - 1

<em>for (i = 0; i < SCORES_SIZE-1; ++i) { </em>

<em>This adds each vector element with the next</em>

<em>        bonusScores.at(i) = bonusScores.at(i) + bonusScores.at(i+1);</em>

<em>  }</em>

The above should be added before

<em>for (i = 0; i < SCORES_SIZE; ++i) { </em>

<em>        cout << bonusScores.at(i) << " "; </em>

<em>}</em>

<em />

<em>Also, I've made other modifications to the program.</em>

  • <em>Proper import of header files</em>
  • <em>Proper declaration of vector bonusScores</em>

<em />

<em>See attachment for complete source code</em>

Download cpp
6 0
3 years ago
As new technological systems develop, old systems become obsolete.<br><br><br> False<br><br> True
uysha [10]

Answer:

true

Explanation:

7 0
3 years ago
Read 2 more answers
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