Answer:
while(userNum>=1){
System.out.print(userNum/2+" ");
userNum--;
}
Explanation:
This is implemented in Java programming language. Below is a complete code which prompts a user for the number, receives and stores this number in the variable userNum.
<em>import java.util.Scanner;</em>
<em>public class TestClock {</em>
<em> public static void main(String[] args) {</em>
<em> Scanner in = new Scanner (System.in);</em>
<em> System.out.println("Enter the number");</em>
<em> int userNum = in.nextInt();</em>
<em> while(userNum>=1){</em>
<em> System.out.print(userNum/2+" ");</em>
<em> userNum--;</em>
<em> }</em>
<em> }</em>
<em>}</em>
The condition for the while statement is userNum>=1 and after each iteration we subtract 1 from the value of userNum until reaching 1 (Hence userNum>=1)
Answer:
The method definition to this question can be given as:
Method definition:
public void clear(int[] arr, int num) //define method clear.
{
if (num == 0) //if block
{
return 0; return value.
}
else //else block
{
arr[num - 1] = 0; //assign value in arr.
return arr[]; //return value.
}
}
clear(arr, num - 1); //calling
Explanation:
The description of the above method definition as follows:
- Firstly we define a method that is "clear" that does not return any value because its return type is "void". This method accepts two integer variables that are "arr[] and num" where arr[] is an array variable and num is an integer variable.
- Inside a method, we use a conditional statement in if block we check that num variable value is equal to 0. if this condition is true so, it will return 0 otherwise it will go to else block in else block it will assign value in variable arr[num-1] that is "0" and return arr value.
Answer:
Check the hardware switch on the wireless antenna card that activates the service.
Explanation:
The person works for uCertify Inc as an IT Technician. David, a regular, has just buy a laptop. He still says that he will not link to a wireless connection, although his laptop seems to have an inner wireless app. So, by checking the hardware switch on the wireless antenna card that activates the service, that person resolves the issue.
Mash-up, I believe, is the correct answer.
Could you please reword this question. i don’t get what you’re asking
