I would say D. Usually students aren't expected to fill out the FAFSA till junior or senior year, this is because it is based on household income which may change every year. Also, guidance counselor's can help students on the right track to go to classes. Clubs and/or sports teams look really good on college applications and are usually preferred by colleges.
Answer:
error: incompatible types
Explanation:
Given
The attached code
Required
The output
Variable "a" is declared as float
While p is declared as a pointer to an integer variable
An error of incompatible types will be returned on line 3, <em>int *p = a;</em>
Because the variables are not the same.
To assign a to p*, we have to use type casting.
Hence, (b) is correct
Answer:
The campaign could be improved by 78% if the listed recommendations are followed.
Explanation:
While conducting the following Search advertising program for a few months, Meredith has announced that revenues of its branded goods are beginning to slow. She reviews her Google Advertising Suggestions webpage which states that her campaign's performance ranking is 22 points.
Thus, the campaign will be increased by 78% if the above recommendations are implemented to inform Meredith regarding its Google Search Advertising plan.
Answer:
See explaination for the program code
Explanation:
The code below
Pseudo-code:
//each item ai is used at most once
isSubsetSum(A[],n,t)//takes array of items of size n, and sum t
{
boolean subset[n+1][t+1];//creating a boolean mtraix
for i=1 to n+1
subset[i][1] = true; //initially setting all first column values as true
for i = 2 to t+1
subset[1][i] = false; //initialy setting all first row values as false
for i=2 to n
{
for j=2 to t
{
if(j<A[i-1])
subset[i][j] = subset[i-1][j];
if (j >= A[i-1])
subset[i][j] = subset[i-1][j] ||
subset[i - 1][j-set[i-1]];
}
}
//returns true if there is a subset with given sum t
//other wise returns false
return subset[n][t];
}
Recurrence relation:
T(n) =T(n-1)+ t//here t is runtime of inner loop, and innner loop will run n times
T(1)=1
solving recurrence:
T(n)=T(n-1)+t
T(n)=T(n-2)+t+t
T(n)=T(n-2)+2t
T(n)=T(n-3)+3t
,,
,
T(n)=T(n-n-1)+(n-1)t
T(n)=T(1)+(n-1)t
T(n)=1+(n-1)t = O(nt)
//so complexity is :O(nt)//where n is number of element, t is given sum
