Answer:
i dont know if this help but To do this, we will use a 'for loop'. The “for loop” allows the programmer to call a section of code repeatedly within a range of values. The range() function will return integer values depending on the arguments.
Explanation:
Answer:
The explanation is for 10 inputs though. You'd have to follow these steps to find input 50 numbers.
Explanation:
This is how I wrote it in the Plain English programming language which looks like pseudo-code but compiles and runs (to save you all the rest of the steps):
To run:
Start up.
Write "Enter 10 numbers separated by spaces: " on the console.
Read a reply from the console.
Loop.
If the reply is blank, break.
Get a number from the reply.
Add 1 to a count.
Add the number to a total.
Repeat.
Write "The total is: " then the total on the console.
Put the total divided by the count into an average.
Write "The average is: " then the average on the console.
Refresh the screen.
Wait for the escape key.
Shut down.
Answer:
below is a Shell I have ;
1.Import java.nio.file.*;
2.Import java.nio.file attribute.*;
3.Import java.10 Exception;
4.public class FileStatistics
5.{
6.public static void main(string []args)
7.{
8.path file=
9.
paths.get("C:\\Java\\chapter.13\\TestData.txt")
10.try
11.{
12.\\declare count and then display path, file, name and folder name.
13.
14.
15.
16.\\declare a BasicFileAttributes object, then add statements to display the file's size and creation time.
17.
18.}
19.
20.catch (10 Exception e)
21.{
22.\\add display 10 Exception
23.
24.}
25.}
Nah I don't there is a BUNCH of creeps on Facebook so no!
