Answer:
t_a = 7 s
t_w = 5 s
Step-by-step explanation:
Given:
- The average speed in air v_a = 16 m/s
- The average speed in water v_w = 3 m/s
- The total distance D = 127 m
- The total time T = 12 s
Find:
How long did the stone fall in air and how long did it fall in the water?
Solution:
- Lets time taken by stone to drop through air as t_a = t_a.
- The time taken in water would be t_w = (12 - t_a)
- The total distance covered can be calculated as:
D = v_a*t_a+ v_w*(12 - t_a)
127 = 16*t_a + 3*(12 - t_a)
Simplify and solve for t:
91 = 16*t_a - 3t_a
13*t_a = 91
t_a = 7 s
t_w = 5 s
(x+6)(x+9) = 0
x+6 = 0 or x+9 = 0
x = -6 x = -9
Answer is A. -6 and -9
Answer:
See explanation below.
Step-by-step explanation:
First I'm going to find angle 2. Angle two plus 55 is equal to 115. 180-115=65. 65-55=10 Angle 2 = 10
Next, we can find angle 3. 55+10=65. 180-65=115. Angle 3 = 115
Angle 2 is equal to angle 5, angle 3 is equal to angle 6, and angle 4 is equal to 55.
Angle 5 = 10
Angle 4 = 55
Angle 6 = 115
Now we can find angle 8. 180-115=65. Angle 8 = 65
Angle 11 = 65
Angle 12 = 115
10+115=125 Angle 10 = 125
180-125 = 55 Angle 9 = 55
Angle 14 = 55
Angle 13 = 125
