Ida needs to hire a singer for her wedding. Singer A is offering his services for an initial $80 in addition to $14.25 per hour.

Question

3 years ago

8

Ida needs to hire a singer for her wedding. Singer A is offering his services for an initial $80 in addition to $14.25 per hour.

Singer B is offering her services for an initial $92 in addition to $12.55 per hour. When will the two singers charge the same amount of money? If necessary, round your answer to the nearest tenth.

Mathematics

2 answers:

Reptile [31] · Answer 1 · 2022-07-04T09:55:38+03:00

Reptile [31]3 years ago

8 0

Singer A

80+14.25h

Singer B

92 +12.55 h

set them equal

80+14.25h= 92 +12.55 h

subtract 12.55h from each side

80 + 1.7 h = 92

subtract 80 from each side

1.7 h =12

divide by 1.7

h =7.0588

h = 7.1 hours

LuckyWell [14K] · Answer 2 · 2022-07-04T11:38:23+03:00

It would take them 7.1 hours to charge the same amount

The equation for Singer A is:

80x + 14.25

The equation for Singer B is:

92 + 12.55x

x would be the number of hours

To figure out when they would charge the the same amount, set them equal to each other:

80 + 14.25x = 92 + 12.55x

Subtract 80 to both sides because whatever you do on one side you have to do it on the other side

14.25x = 12 + 12.55x

Subtract 12.55x

1.7x = 12

Divide by 1.7

x = 7.0588

Which is also

x = 7.1 hours