Rick took a 45-minute lunch break. At the end of the break, it was 1:00 P.M. What time did Rick start his lunch break?

A loaf of bread costs $1.40 and the markup is 30% of the selling price. Find the selling price.

andreev551 [17]

Answer:

The selling price after the markup is $1.82

Step-by-step explanation:

$1.40 * .30 =

Multiply $1.40 times .30 (which is same as 30%)

$1.40 * .30 = $0.42

Add $1.40 and $0.42

= $1.82

Hope this helps.

6 0

3 years ago

Torque (or moment) is the measure of turning force or twist on an object. If a mechanic is applying 12 Newton centimeters of tor

SashulF [63]

Answer:

1.0638

Step-by-step explanation:

Given the question:

If a mechanic is applying 12 Newton centimeters of torque on a bolt how many pound inches would this be?

Torque = 12 Newton centimeter

Torque which is the turning effect on an object :

1 Newton = 0.225 pound force

1 centimeter = 0.394 inch

Hence ;

1 Newton centimeter = (1 × 0.225 × 0.394) = 0.08865 pound inch

12 Newton centimeter is hence, equals :

(12 × 0.225 × 0.394) pound inch

= 1.0638 pound inch

7 0

3 years ago

If a hurricane was headed your way, would you evacuate? The headline of a press release issued January 21, 2009 by the survey re

Nikolay [14]

Answer:

The 98% confidence interval for population proportion of people who refuse evacuation is {0.30, 0.33].

Step-by-step explanation:

The sample drawn is of size, n = 5046.

As the sample size is large, i.e. n > 30, according to the Central limit theorem the sampling distribution of sample proportion will be normally distributed with mean $\hat p$ and standard deviation $\sqrt{\frac{\hat p (1-\hat p)}{n} }$ .

The mean is: $\hat p=0.31$

The confidence level (CL) = 98%

The confidence interval for single proportion is:

$CI_{p}=[\hat p-z_{(\alpha /2)}\times\sqrt{\frac{\hat p (1-\hat p)}{n} },\ \hat p+z_{(\alpha /2)}\times\sqrt{\frac{\hat p (1-\hat p)}{n} }]$

Here $z_{(\alpha /2)}$ = critical value and α = significance level.

Compute the value of α as follows:

$\alpha =1-CL\\=1-0.98\\=0.02$

For α = 0.02 the critical value can be computed from the z table.

Then the value of $z_{(\alpha /2)}$ is ± 2.33.

The 98% confidence interval for population proportion is:

$CI_{p}=[\hat p-z_{(\alpha /2)}\times\sqrt{\frac{\hat p (1-\hat p)}{n} },\ \hat p+z_{(\alpha /2)}\times\sqrt{\frac{\hat p (1-\hat p)}{n} }]\\=[0.31-2.33\times \sqrt{\frac{0.31\times(1-0.33)}{5046} },\ 0.31+2.33\times \sqrt{\frac{0.31\times(1-0.33)}{5046} } ]\\=[0.31-0.0152,\ 0.31+0.0152]\\=[0.2948,0.3252]\\\approx[0.30,\ 0.33]$

Thus, the 98% confidence interval [0.30, 0.33] implies that there is a 0.98 probability that the population proportion of people who refuse evacuation is between 0.30 and 0.33.

7 0

3 years ago

What is the scale factor and x value?

Ksivusya [100]

Don’t click on the li

4 0

3 years ago

The composite figure is made up of a triangular prism and a pyramid. The two solids have congruent bases. What is the volume of

Brums [2.3K]

The complete question in the attached figure

we know that
[volume of a cone]=[area of the base]*h/3
[area of the base]=22*10/2-------> 110 units²
h=19.5 units
[volume of a cone]=[110]*19.5/3------> 715 units³

[volume of a triangular prism]=[area of the base]*h
[area of the base]=110 units²
h=25 units
[volume of a a triangular prism]=[110]*25------------> 2750 units³

[volume of a the composite figure]=[volume of a cone]+[volume of a a triangular prism]
[volume of a the composite figure]=[715]+[2750]-------> 3465 units³

the answer is
The volume of a the composite figure is 3465 units³

8 0

3 years ago

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