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Angelina_Jolie [31]

3 years ago

10

Find the length of the base of the following pyramid, given the height of the pyramid is 211 meters and the angle of elevation o

f the base of the
pyramid is 62. Round to the nearest whole number. (4 points)
h = 211 m
62
length of the base

1 answer:

jek_recluse [69]3 years ago

6 0

Answer:

use formula length × width ×height

Step-by-step explanation:

plug in what they have given you

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I need help with both please no links!

nlexa [21]

Answer:

The first one- 24, The second one-B

Step-by-step explanation:

The first one-Top corner=110, 110+46=156, 180-156=24

The other one-I have no clue how to explain it

4 0

2 years ago

What to plot on the graph

Tems11 [23]

just put a dot on the number line where 0, 3, and -3 are

6 0

3 years ago

When f(x)=5x^2-2x+5, evaluate f(-3)

patriot [66]

Answer:

f(-3)=56

Step-by-step explanation:

When evaluating a specific input for a function, you just plug that input in for x.

So in this case, f(-3)=5(-3)^2-2(-3)+5

f(-3)=5(-3)^2-2(-3)+5

f(-3)=5(9)+6+5

f(-3)=45+6+5

f(-3)=56

8 0

2 years ago

Jim was thinking of a number. Jim adds 20 to it, then doubles it and gets an answer of 99.2. What was the original number?

azamat

Alright, lets get started.

Jim was thinking of a number.

Suppose the number Jim was thinking, is x.

Jim adds 20 to it means number will be = $x+20$

And Jim doubles it, means $2*(x+20)$

Jim gets 99.2 and as per us, he gets $2*(x+20)$

So, making them equal

$2(x+20)=99.2$

$2x+40=99.2$

Subtracting 40 in both sides

$2x+40-40=99.2-40$

$2x=59.2$

$x=29.6$

It means the original number is 29.6. : Answer

Hope it will help :)

6 0

2 years ago

Determine the formula for the nth term of the sequence:<br>-2,1,7,25,79,...

rodikova [14]

A plausible guess might be that the sequence is formed by a degree-4* polynomial,

$x_n = a n^4 + b n^3 + c n^2 + d n + e$

From the given known values of the sequence, we have

$\begin{cases}a+b+c+d+e = -2 \\ 16 a + 8 b + 4 c + 2 d + e = 1 \\ 81 a + 27 b + 9 c + 3 d + e = 7 \\ 256 a + 64 b + 16 c + 4 d + e = 25 \\ 625 a + 125 b + 25 c + 5 d + e = 79\end{cases}$

Solving the system yields coefficients

$a=\dfrac58, b=-\dfrac{19}4, c=\dfrac{115}8, d = -\dfrac{65}4, e=4$

so that the n-th term in the sequence might be

$\displaystyle x_n = \boxed{\frac{5 n^4}{8}-\frac{19 n^3}{4}+\frac{115 n^2}{8}-\frac{65 n}{4}+4}$

Then the next few terms in the sequence could very well be

$\{-2, 1, 7, 25, 79, 208, 466, 922, 1660, 2779, \ldots\}$

It would be much easier to confirm this had the given sequence provided just one more term...

* Why degree-4? This rests on the assumption that the higher-order forward differences of $\{x_n\}$ eventually form a constant sequence. But we only have enough information to find one term in the sequence of 4th-order differences. Denote the k-th-order forward differences of $\{x_n\}$ by $\Delta^{k}\{x_n\}$ . Then

• 1st-order differences:

$\Delta\{x_n\} = \{1-(-2), 7-1, 25-7, 79-25,\ldots\} = \{3,6,18,54,\ldots\}$

• 2nd-order differences:

$\Delta^2\{x_n\} = \{6-3,18-6,54-18,\ldots\} = \{3,12,36,\ldots\}$

• 3rd-order differences:

$\Delta^3\{x_n\} = \{12-3, 36-12,\ldots\} = \{9,24,\ldots\}$

• 4th-order differences:

$\Delta^4\{x_n\} = \{24-9,\ldots\} = \{15,\ldots\}$

From here I made the assumption that $\Delta^4\{x_n\}$ is the constant sequence {15, 15, 15, …}. This implies $\Delta^3\{x_n\}$ forms an arithmetic/linear sequence, which implies $\Delta^2\{x_n\}$ forms a quadratic sequence, and so on up $\{x_n\}$ forming a quartic sequence. Then we can use the method of undetermined coefficients to find it.

5 0

2 years ago