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3 years ago

Write an expression equivalent to b^10/b^5 in the form b^m.

Mathematics

1 answer:

Mars2501 [29]3 years ago

4 0

B^5 when you’re dividing exponents, just subtract!

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Simplify the expression (-4)(9)/(-6) 6 –36 36 –6

DaniilM [7]

(-4)(9)/(-6)

= -36/(-6)

= 6 answer

7 0

3 years ago

What is the rate of change on the table above A) -1/3 B) 1/2 C) -1/4 D) 1/5

nirvana33 [79]

answer is option D

$\frac{2}{10} = \frac{1}{5} \\ \frac{4}{20} = \frac{1}{5} \\ \frac{6}{30} = \frac{1}{5} \\ \frac{8}{40} = \frac{1}{5}$

so the answer is option D

please mark this answer as brainlist

4 0

3 years ago

lesantik [10]

Answer:

x = (64 + 5) ÷ 3

Step-by-step explanation:

3x - 5 = 64

Add 5 to both sides: 3x = 64 + 5 = 69

Divide both sides by 3: x = 69 ÷ 3 = 23

So the answer is x = (64 + 5) ÷ 3

Note: If we didn't add the parentheses then using the order of operation x = 64 + 5 ÷ 3 would be x = 64 + $\frac{5}{3}$ = 65 $\frac{2}{3}$

8 0

3 years ago

Equation of the line that passes through the points (0,6) and (-5,2)?

Anarel [89]

Answer:

fsdfd

Step-by-step explanation:

5 0

3 years ago

One particular 13-foot tall cone of dry sand has a base diameter of 38.6 feet. To the nearest tenth of a degree, what is the ang

Nataly_w [17]

34.0 degrees, 29.6 feet in Diameter.
This is a right triangle trigonometry question.
Use half of the diameter to form the base of the triangle (19.3 ft) with a height 0f 13.
Use Inverse Tangent function to find the angle of repose
$tan ^{-1}(\frac{Opposite}{Adjacent} ) = Angle of repose$

$tan ^{-1}(\frac{13}{19.3} ) = 33.96$ round to 34.0

then use the angle of repose to solve trigonometric function of the tangent for the radius of the other cone.

$tan(Angle)= \frac{opp}{adj}$

$tan(34)=(\frac{10}{x} )$

switch denominator and tangent

$x=(\frac{10}{tan(34)} ) =14.82$
multiply by 2 to get diameter of second cone
14.82*2≈29.6

6 0

3 years ago