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GrogVix [38]
3 years ago
5

Last month, you spent $87 on clothing. This month you spent 165% of what you spent last month. How much did you spend this month

?
Mathematics
1 answer:
nordsb [41]3 years ago
3 0

143.55 87x165% or 87x1.65

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sergey [27]

Answer:

A. 20mg

Step-by-step explanation:

\frac{75lbs}{60mg} *\frac{25lbs}{y}

Cross multiply and divide.

60 × 25 = 1500

1500 ÷ 75 = 20

<em>good luck, hope this helps :)</em>

6 0
3 years ago
The three incoming currents at a node in an electrical current measure .7 amps, .68amps, .47 amps. two of the three outgoing cur
irakobra [83]
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4 years ago
How do you determine the base when solving for x by converting to a log?
worty [1.4K]

$x=\frac{\ln \left(\frac{3}{2}\right)}{4 \ln (1.0125)}

Solution:

Given expression:

$(1.0125)^{4 x}=\frac{3}{2}

To solve the expression:

$(1.0125)^{4 x}=\frac{3}{2}

<em>If f(x) = g(x) then ln(f(x)) = ln(g(x)).</em>

Using the above condition, we can write

$\ln \left(1.0125^{4 x}\right)=\ln \left(\frac{3}{2}\right)

Apply log rule: \log _{a}\left(x^{b}\right)=b \cdot \log _{a}(x)

$4 x \ln (1.0125)=\ln \left(\frac{3}{2}\right)

Divide both side of the equation by 4 \ln (1.0125).

$\frac{4 x \ln (1.0125)}{4 \ln (1.0125)}=\frac{\ln \left(\frac{3}{2}\right)}{4 \ln (1.0125)}

$x=\frac{\ln \left(\frac{3}{2}\right)}{4 \ln (1.0125)}

The answer is x=\frac{\ln \left(\frac{3}{2}\right)}{4 \ln (1.0125)}.

8 0
3 years ago
Approximately how much larger is the population of Pennsylvania than the population of Ohio? Pennsylvania's population is 12,604
nadya68 [22]
Answer= 1 million

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6 0
3 years ago
Read 2 more answers
A gerbil eats about 1/4oz of food per day. About how many pounds of food can a gerbil eat in a year?
jek_recluse [69]
1/4(365) = 365/4 oz = 365/4(16) pound = 365/64 pound
4 0
4 years ago
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