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3 years ago

Determine the solution set of x2 - 80 = 0

2 answers:

meriva3 years ago

8 0

   x² - 80 = 0
Add 80
to each side: x² = 80

Square root
each side: x    = √80

Look it up: x = + 8.944... (rounded)
   and
   x = - 8.944... (rounded).
___________________________________

Here's a cleaner solution:

   x² - 80 = 0
Add 80
to each side: x² = 80

Square root
each side: x    = √80

But 80 = 16 · 5

So √80 = √16 · √5

√16 = 4, so    x = 4 √5

Mekhanik [1.2K]3 years ago

6 0

X^2 -80=0
x^2 =80
x =sqrrt 80

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A box containing tissues has the shape of a rectangular prism measuring 19 inches by 23 inches by 8 inches.

Hatshy [7]

Well to find volume you just have to multiply all 3 lengths so... 19*23*8=A)3496 in^3

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4 years ago

Find the equation of ellipse passing throgh (1,4) and (-3,2)

irinina [24]

Answer:

$\displaystyle \frac{ {3x}^{2} }{ 35 } + \frac{{2y}^{2} }{ 35 } = 1$

Step-by-step explanation:

we want to figure out the ellipse equation which passes through (1,4) and (-3,2)

the standard form of ellipse equation is given by:

$\displaystyle \frac{(x - h {)}^{2} }{ {a}^{2} } + \frac{(y - k {)}^{2} }{ {b}^{2} } = 1$

where:

(h,k) is the centre
a is the horizontal redius
b is the vertical radius

since the centre of the equation is not mentioned, we'd assume it (0,0) therefore our equation will be:

$\displaystyle \frac{ {x}^{2} }{ {a}^{2} } + \frac{{y}^{2} }{ {b}^{2} } = 1$

substituting the value of x and y from the point (1,4),we'd acquire:

$\displaystyle \frac{ 1}{ {a}^{2} } + \frac{16}{ {b}^{2} } = 1$

similarly using the point (-3,2), we'd obtain:

$\displaystyle \frac{ 9}{ {a}^{2} } + \frac{4 }{ {b}^{2} } = 1$

let 1/a² and 1/b² be q and p respectively and transform the equation:

$\displaystyle \begin{cases} q + 16p = 1 \\ 9q + 4p = 1 \end{cases}$

solving the system of linear equation will yield:

$\displaystyle \begin{cases} q = \dfrac{3}{35} \\ \\ p = \dfrac{2}{35} \end{cases}$

substitute back:

$\displaystyle \begin{cases} \dfrac{1}{ {a}^{2} } = \dfrac{3}{35} \\ \\ \dfrac{1}{ {b}^{2} } = \dfrac{2}{35} \end{cases}$

divide both equation by 1 which yields:

$\displaystyle \begin{cases} {a}^{2} = \dfrac{35}{ 3} \\ \\ {b}^{2} = \dfrac{35}{2} \end{cases}$

substitute the value of a² and b² in the ellipse equation , thus:

$\displaystyle \frac{ {x}^{2} }{ \dfrac{35}{3} } + \frac{{y}^{2} }{ \dfrac{35}{2} } = 1$

simplify complex fraction:

$\displaystyle \frac{ {3x}^{2} }{ 35 } + \frac{{2y}^{2} }{ 35 } = 1$

and we're done!

(refer the attachment as well)

8 0

3 years ago

Pair if trousers for 75 cedis and sold at 80 cedis. calculate the percentage profit

Artyom0805 [142]

Answer:

6.7%

Step-by-step explanation:

cost: 75 cedis

sale price: 80 cedis

amount of profit: 80 cedis - 75 cedis = 5 cedis

Now we find what percent 5 cedis is of 75 cedis.

percent = part/whole * 100%

percent = 5/75 * 100%

percent = 0.06666 * 100%

percent = 6.6666%

percent = 6.7%

3 0

3 years ago

(1) D. Generalize Explain your procedure for calculating the profit

SIZIF [17.4K]

Answer:

$1,650 profit

Step-by-step explanation:

It cost $15 to groom one animal, if you groom 95 animals you would do 95 animals x $15 = $1,425 profit. If you groom 110 animals and charge $15 per animal you would do the same equation. 110 animals x $15 = $1,650. The equation for this problem is the number of animals groomed X the cost to groom one animal.

Hope this helps!

8 0

2 years ago

Choose the correct simplification of the expression 3b/a-2

Goshia [24]

To solving with their equation and expression to step by step.

3b/a-2

= -2a+3b/a

4 0

3 years ago

Read 2 more answers