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3 years ago

7

Is 2 8/9 equivalent to 3 1/6?

2 answers:

Zielflug [23.3K]3 years ago

8 0

Answer:

No

Step-by-step explanation:

expeople1 [14]3 years ago

8 0

Answer:

The answer is No.

Step-by-step explanation:

have a great day

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Joe is trying to find out how many cubic centimeters of sand he can fit in a hole he dug in his backyard. The size of the hole i

Agata [3.3K]

Joe is trying to find out how many cubic centimeters of sand he can fit in a hole he dug in his backyard. The size of the hole is shown in the diagram. Which of the equations will yield the correct answer?

The correct answer is :
A) V = 9.1(2.2)(3.8)

Hope this helps!

7 0

3 years ago

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I need help please help me

harkovskaia [24]

We substitute in c using 9, it will be as follows:
5 ×[(-6×9)+4] = 5 × (-54+4) = 5 × (-50) = -250

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3 years ago

Dante's Mom wants to build a fence around their yard. Here are the measurements of the yard. What are the measurements of the mi

timama [110]

Answer:

(a)The missing measurements are 9 feet and $16\frac{1}{4}$ feet$ .

(b)Therefore, the length of the fence is $97\frac{1}{2}$ feet$

Step-by-step explanation:

The diagram of the yard is attached below.

(a)I have labeled the missing dimensions of the yard as x and y.

Therefore:

$y+8\frac{1}{4}=17 \frac{1}{4}\\y=17 \frac{1}{4}-8\frac{1}{4}\\y=9$ feet$

Similarly:

$x+15\frac{1}{4}=31\frac{1}{2}\\x=31\frac{1}{2}-15\frac{1}{4}\\x=31-15+\frac{1}{2}-\frac{1}{4}\\x=16+\frac{1}{4}\\x=16\frac{1}{4}$ feet$

The missing measurements are 9 feet and $16\frac{1}{4}$ feet$ .

(b)Length of the Fence

The fence is rectangular shaped with:

Length = $31\frac{1}{2}$ feet$

Width = $17 \frac{1}{4}$ feet$

Perimeter of a Rectangle = 2(L+W)

Therefore, the length of the fence

$=2(31\frac{1}{2}+17 \frac{1}{4})\\=2(31+17+\frac{1}{2}+ \frac{1}{4})\\=2(48+ \frac{3}{4})\\=96+\frac{3}{2}\\=97\frac{1}{2}$ feet$

8 0

4 years ago

What is the approximate distance between the points (1,-2) and (-9,3) on a coordinate grid

jeka57 [31]

<u>Answer</u>

$5\sqrt{5}$ ≈ 11.1803398874989485

<u>Detailed Explanation </u>

We will be using the distance formula for this problem

$\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}$

Now, let's input the numbers into the formula.

$\sqrt{\left(-9-1\right)^2+\left(3-\left(-2\right)\right)^2}$

Solve.

Therefore, the distance between the two points is

$5\sqrt{5}$ ≈ 11.1803398874989485

3 0

3 years ago

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Dimas [21]

For C at 7pm they sold most and at 6 am they sold less

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3 years ago

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