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3 years ago

Difference between an integer and a real number

Mathematics

2 answers:

notsponge [240]3 years ago

4 0

Guguvyftcgxfctc ull busy

jenyasd209 [6]3 years ago

3 0

Answer:

Real number is any number. This includes integers, rational, and irrational numbers.

While integers are just positive or negative whole numbers that also includes 0.

Hope this helps!

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Wanting someone to help me with the procedures<br>n²+n=120<br><br>

Natali [406]

N^2 + n - 120 = 0

Quadratic formula
a = 1, b = 1, c = -120
n = [-1 plus or minus root(1^2 - 4(1)(-120))] / 2(1)
n = (-1 plus or minus root481)/2
n =(approximately) 10.5 or -11.5

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3 years ago

PLEASE HELP ME IN MATH

maks197457 [2]

Answer:

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Step-by-step explanation:

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2 years ago

Rewrite in simplest rational exponent form √x • 4√x. Show each step of your process.

Vikentia [17]

Step-by-step explanation:

$= \sqrt{x} .4 \sqrt{x}$

$= {x}^{ \frac{1}{2} } \times 4 {x}^{ \frac{1}{2} }$

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2 years ago

<img src="https://tex.z-dn.net/?f=%20%5Cboxed%7B%5Cboxed%7B%20%5Cbegin%7Barray%7D%7B%7D%5Clarge%5Ctt%20The%20%20%5C%5C%20%20%5Ct

larisa86 [58]

Distance formula

$\boxed{\sf \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}}$

Now

$\\ \tt\Rrightarrow AB=\sqrt{(3-3)^2+(-2-8)^2}=\sqrt{100}=10units$

$\\ \tt\Rrightarrow OK=\sqrt{(5-7)^2+(-2+2)^2}=\sqrt{4}=2units$

$\\ \tt\Rrightarrow LM=\sqrt{(-4-4)^2+(6+4)^2}=\sqrt{64+100}=\sqrt{164}\approx 13units$

$\\ \tt\Rrightarrow PC=\sqrt{(5-2)^2+(1-3)^2}=\sqrt{9+4}=\sqrt{13}=3.2units$

$\\ \tt\Rrightarrow QR=\sqrt{(-2+10)^2+(3-9)^2}=\sqrt{64+36}=\sqrt{100}=10units$

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2 years ago

Read 2 more answers

Could someone help me please

astraxan [27]

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3 years ago