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2 years ago

Write a linear function f withe the values f (10) = 5 and f (2) = -3

Mathematics

1 answer:

MakcuM [25]2 years ago

8 0

Answer:

(a) $f(x)=\frac{1}{2}x$

(b) $f(x)=-\frac{3}{2}x$

Step-by-step explanation:

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At a real estate agency, an agent sold a house for $360,000. The commission rate is 25% for the real estate agency and the com

Orlov [11]

Answer: See explanation

Step-by-step explanation:

a. The amount that the agency make on the house will be 25% of $360,000. This will be:

= 25% × $360,000

= 25/100 × $360,000

= 0.25 × $360,000

= $90,000

b. The amount that the agent earn in commission will be:

= 30% × $90,000

= 30/100 × $90,000

= 0.3 × $90,000

= $27,000

3 0

2 years ago

Sorry last question :(

elena55 [62]

Area of rectangle=30•12=360 square meters
Area of semicircle=3.14•15•15=353.25 square meters
360+353.25=713.25 square meters

6 0

3 years ago

How do you solve f(x) = x2 + x - 20?

Darina [25.2K]

$\huge \bf༆ Answer ༄$

Let's solve ~

${ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \: {x}^{2} + x - 20$

${ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \: {x}^{2} + 5x - 4x - 20$

${ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \:x(x + 5) - 4(x + 5)$

${ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \:(x + 5)(x - 4)$

It's factorized now ~ And if you want to find the zeros then equate the expression with 0.

And you will get ;

${ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \:x = - 5 \: \: and \: \: 4$

4 0

1 year ago

M is the midpoint of AN, A has coordinates

maksim [4K]

Step-by-step explanation:

According to Question , M is the midpoint of AN, A has coordinates (-7,4), and M has coordinates (-4, -1).

Figure :-

$\setlength{\unitlength}{1 cm}\begin{picture}(20,12) \put(4,0.2){\line(0,-1){0.4}}\put(1,0){\line(1,0){6}} \put(3.8,-0.6){$\bf M(-4,-1) $} \put(1,-0.6){$\bf A (-7,4)$} \put(6.8,-0.6){$\bf N(x,y)$} \end{picture}$

Let the coordinates of N be ( x , y )

Now , according to Midpoint Formula , the midpoint of points say A(x , y) and B (x' , y') is given by ,

$\boxed{\blue{ \bf Midpoint =\bigg( \dfrac{x+x'}{2} , \dfrac{y+y'}{2} \bigg) }}$

On using this formula ,

$=> Midpoint = \bigg( \dfrac{x+x'}{2} , \dfrac{y+y'}{2} \bigg) \\ \\ => (-4, 1) = \bigg( \dfrac{x -7 }{2} , \dfrac{y + 4 }{2}\bigg) \\ \\ => -4 = \dfrac{x-7}{2} \\\\ => x - 7 = -8 \\\\ => x = 7 -8 \\\\ \boxed{\red{\sf=> x = -1 }} \\\\ => \dfrac{y+4}{2}=-1 \\\\=> y +4 = -2 \\ \\ y = -4-2 \\\\\boxed{\red{\sf=> y = -6 }}$