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2 years ago

Solve for x7(x 2) (x 5)44O -16

Mathematics

1 answer:

babymother [125]2 years ago

3 0

7(x + 2) = 6(x + 5)

7x + 14 = 6x + 30 |subtract 14 from both sides

7x = 6x + 16 |subtract 6x from both sides

x = 16

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A tank contains 10 liters of pure water. Saline solution with a variable concentration 5 grams of salt per liter is pumped into

algol [13]

Answer:

dQ(t)/dt = 20 - 2Q(t)/5 , Q(0) = 0

Step-by-step explanation:

The mass flow rate dQ(t)/dt = mass flowing in - mass flowing out

Since 5 g/L of salt is pumped in at a rate of 4 L/min, the mass flow in is thus 5 g/L × 4 L/min = 20 g/min.

Let Q(t) be the mass present at any time, t. The concentration at any time ,t is thus Q(t)/volume = Q(t)/10. Since water drains at a rate of 4 L/min, the mass flow out is thus, Q(t)/10 g/L × 4 L/min = 2Q(t)/5 g/min.

So, dQ(t)/dt = mass flowing in - mass flowing out

dQ(t)/dt = 20 g/min - 2Q(t)/5 g/min

Since the salt just begins to be pumped in, the initial mass of salt in the tank is zero. So Q(0) = 0

So, the initial value problem is thus

dQ(t)/dt = 20 - 2Q(t)/5 , Q(0) = 0

3 0

1 year ago

Pls help me pls i will give brainlist

Andre45 [30]

Answer:

1. Pour the mixture through a filter to separate the sand; 2. Evaporate the liquid to separate the salt.

Step-by-step explanation:

6 0

2 years ago

Kim solved the equation below by graphing a system of equations. log base 2 (3x-1) = log base 4 (x+8)

kompoz [17]

Answer:

solution is

$x=1.353,y=1.613$

Step-by-step explanation:

We are given equation as

$log_2(3x-1)=log_4(x+8)$

Firstly, we will find equations

First equation is

$y=log_2(3x-1)$

Second equation is

$y=log_4(x+8)$

now, we can draw graph

and then we can find intersection point

we can see that

intersection point is (1.353,1.613)

so, solution is

$x=1.353,y=1.613$

8 0

2 years ago

Read 2 more answers

Bulletin board is 8 feet long and 5 feet wide. How many feet of border does it need?

Musya8 [376]

8 × 5 = 40

So the border has to be 40 feet.

Hope this helps!

Work:

length × width = answer

length = 8
width = 5
answer = 40

7 0

2 years ago

Read 2 more answers

UDD Question 6 10 pts Solve for x. Round to the nearest tenth (one decimal place). Just type the number, no unit of measurement.

NISA [10]

Answer:

The answer is;

54.4

Step-by-step explanation:

The given parameter are;

Triangle ΔFGH = Right triangle

The length of segment $\overline {FH}$ = 48

The measure of ∠HFG = 28°

The measurement required = The measure of segment $\overline {FG}$ = x

The measure of ∠FHG = 90° angle opposite hypotenuse side of a right triangle

Therefore, ∠FGH = 180° - ∠HFG - ∠FHG = 180° - 90° - 28° = 62°

∠FGH = 62°

By sine rule, we have;

$\overline {FH}$ /(sin ∠FGH) = $\overline {FG}$ /(sin(∠FHG)

By substituting the known values, we have;

48/(sin 62°) = x/(sin(90°)

sin(90°) = 1, therefore, we have;

x/1 = x = 48/(sin 62°) = 54.4 (by rounding the answer to the nearest tenth)

x = 54.4

8 0

1 year ago