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Answer:
The minimum percentage of noise level readings within 8 standard deviations of the mean is 98.44%.
Step-by-step explanation:
When we do not know the shape of the distribution, we use the Chebyshev's Theorem to find the minimum percentage of a measure within k standard deviations of the mean.
This percentage is:
Within 8 standard deviations of the mean
This means that . So
The minimum percentage of noise level readings within 8 standard deviations of the mean is 98.44%.