Answer:
<h2>49.5°</h2>
Step-by-step explanation:
Given the trigonometry function as shown sin W = 0.79, to get W, the following steps must be followed.
Step 1: Take the arcsin of both sides of the equation
Step 2: Use a calculator to get the resulting value of W
(to nearest tenth of a degree)
This gives the acute angle needed.
Note that acute angle are angles that are less than 90°
Answer:
1.
Vert. asymptote: x = {-3, 2}
Horiz. asymptote: y = 0
x-int: None
Question 3.
a. There is no hole
b. Vert. asymptote: x = {-2, 2}
c. f(x) = 0: x = {0, -1/2}
d. The graph has no hole at (-2, 4)
Question 4.
a. Vert. asymptote: x = {-2, 2}
b. f(x) = 0: x = {0, -1/2}
c. Horizontal asymptote: y = 2
d. The graph has no hole
I'm a bit confused. Some of the things stated in the question aren't true like how there are holes in places where there aren't.
H(t) = 0 for t = 7 and for t = -2.
It is reasonable for the time to be positive, 7 seconds.
(The offered answers all appear to be negative, so none are reasonable.)
