400$
Explanation:
In 1992, the price is 28000$ and 9600$ in 1996 so in 4 years the value the car lost is 18400$
Dividing 18400 by 4 years we get 4600 depreciation value per year.
Between 1996 and 1998 there is 2 years
So in 1998 the value of the car will be:
9600 (value in 1996) - 2x4600 = 400$
Answer:
3
Step-by-step explanation:
f(3) = 3(3)-4
f(3)= 9-4
f(3) = 5
g(2) = (2)
g(2) = 2
f(3)-g(2) = ?
(5) - (2) = ?
(5) - (2) = 3
Answer:
£1837.5
Step-by-step explanation:
Given data
Cost of car P= £2100.
Rate r= 2.2%
Time t= 6 years
Now we want to find the worth after 6 years, let us apply the compound interest expression but this time for depreciation
A= P(1-r)^t
Substitute
A= 2100(1-0.022)^6
A= 2100*(0.978)^6
A= 2100*0.875
A= £1837.5
Hence the amount of the car after 6 years is £1837.5