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3 years ago

Please help WILL MARK BRAINLIEST! (random answers will be reported)

Mathematics

2 answers:

bixtya [17]3 years ago

6 0

Answer:

Step-by-step explanation:

The formula for volume of a cylinder is V = π $r^{2}$ h. We replace r with the radius (to find it just divide the diameter by 2), which is 2.5. Hope this helped!! :]

Pachacha [2.7K]3 years ago

6 0

The answer is C I am positive

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ratelena [41]

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3 years ago

Danika has one apple that weighs 1/4 lb and another apple weighs 3/16 lb. Find the DIFFERENCE in their weights.

Mama L [17]

Answer: A.

Step-by-step explanation:

Danika has 1/4 lb apple and a 3/16 apple. We have to find a common denominator to be able to subtract them. We can do this by finding out 4 times how much equals 16. Which is 4. So you multiply both of the numbers by 4, (1x4 = 4 , 4x4 = 16) being 4/16. Now you just have to subtract the top numbers "4-3 = 1" 1/16.

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2 years ago

Read 2 more answers

For the person who were helping me

Fittoniya [83]

Take 1600 and 85% (turn 85% into a decimal .85) and multiply them together. you should get that 1360 tickets were sold. hope this helps and please give me the brainliest answer.

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2 years ago

The Bessel function or order zero of the first kind may be defined by. Find the radius of convergence of J0(x).

fenix001 [56]

Answer:

Step-by-step explanation:

The Bessel function or order zero of the first kind may be defined by the solution - to Bessel's differential equation - which is a finite value at the origin X=0 for positive or negative whole numbers (integers) or positive alpha (α) values.

6 0

3 years ago

The logistic equation for the population (in thousands) of a certain species is given by:

Eva8 [605]

Answer:

b. 1.5

c. 1.5

d. No

Step-by-step explanation:

a. First, let's solve the differential equation:

$\frac{dp}{dt} =3p-2p^2$

Divide both sides by $3p-2p^2$ and multiply both sides by dt:

$\frac{dp}{3p-2p^2}=dt$

Integrate both sides:

$\int\ \frac{1}{3p-2p^2} dp =\int\ dt$

Evaluate the integrals and simplify:

$p(t)=\frac{3e^{3t} }{C_1+2e^{3t}}$

Where C1 is an arbitrary constant

I sketched the direction field using a computer software. You can see it in the picture that I attached you.

b. First let's find the constant C1 for the initial condition given:

$p(0)=3=\frac{3e^{0} }{C_1+2e^{0} } =\frac{3}{C_1+2}$

Solving for C1:

$C_1=-1$

Now, let's evaluate the limit:

$\lim_{t \to \infty} \frac{3e^{3t} }{2e^{3t}-1 } \\\\Divide\hspace{3}the\hspace{3}numerator\hspace{3}and\hspace{3}denominator\hspace{3}by\hspace{3}e^{3t} \\\\ \lim_{t \to \infty} \frac{3 }{2-e^{-3x} }$

The expression $-e^{-3x}$ tends to zero as x approaches ∞ . Hence:

$\lim_{t \to \infty} \frac{3e^{3t} }{2e^{3t}-1 } =\frac{3}{2} =1.5$

c. As we did before, let's find the constant C1 for the initial condition given:

$p(0)=0.8=\frac{3e^{0} }{C_1+2e^{0} } =\frac{3}{C_1+2}$

Solving for C1:

$C_1=1.75$

Now, let's evaluate the limit:

$\lim_{t \to \infty} \frac{3e^{3t} }{2e^{3t}+1.75 } \\\\Divide\hspace{3}the\hspace{3}numerator\hspace{3}and\hspace{3}denominator\hspace{3}by\hspace{3}e^{3t} \\\\ \lim_{t \to \infty} \frac{3 }{2+1.75e^{-3x} }$

The expression $-e^{-3x}$ tends to zero as x approaches ∞ . Hence:

$\lim_{t \to \infty} \frac{3e^{3t} }{2e^{3t}+1.75 } =\frac{3}{2} =1.5$

d. To figure out that, we need to do the same procedure as we did before. So, let's find the constant C1 for the initial condition given:

$p(0)=2=\frac{3e^{0} }{C_1+2e^{0} } =\frac{3}{C_1+2}$

Solving for C1:

$C_1=-\frac{1}{2} =-0.5$

Can a population of 2000 ever decline to 800? well, let's find the limit of the function when it approaches to ∞:

$\lim_{t \to \infty} \frac{3e^{3t} }{2e^{3t}-0.5 } \\\\Divide\hspace{3}the\hspace{3}numerator\hspace{3}and\hspace{3}denominator\hspace{3}by\hspace{3}e^{3t} \\\\ \lim_{t \to \infty} \frac{3 }{2-0.5e^{-3x} }$

The expression $-e^{-3x}$ tends to zero as x approaches ∞ . Hence:

$\lim_{t \to \infty} \frac{3e^{3t} }{2e^{3t}-0.5 } =\frac{3}{2} =1.5$

Therefore, a population of 2000 never will decline to 800.

6 0

3 years ago