Answer:
B.) 80 cans, 20 brushes
Step-by-step explanation:
Let the cans of paint be represented by variable <em>p</em> , and brushes by variable <em>b</em>
The first equation would be ; p + b = 100
p = 100 - b
The second equation would be;
8p + 12b = 880
Replace p in the equation by (100-b);
=8(100-b) + 12b =880
=800 - 8b +12b = 880
= subtract 800 from both sides to get;
4b = 880-800
4b = 80
divide both sides by 4 to solve for b;
b= 80/4
b = 20
If p + b = 100, then p+20 = 100
p = 100-20
p = 80
Therefore, they sold 80 cans of paint and 20 brushes
The answer is 2/3 I think
I will give you the answer if you give me brainliest answer
<span>What is the area of a rectangular yard if 2 of the sides have lengths of 30 yds and 22 yds?
</span>660 sq yds
If the perimeter of a triangle is 19 cm. The lengths of 3 sides is: a = 8, b = 7, c = 4.
<h3>Parimeter</h3>
Let a = longest
Let b= shortest
Let c= third side
a = 2c
a = (b+ c) - 3
a + 3 = b + c
Using three variables to solve the expression for perimeter
Perimeter= 19 cm
a+ b + c = 19
a + (a + 3) = 19
2a + 3 = 19
2a= 16
Divide both side by 2a
a=16/2
a = 8
a = 2c
8 = 2c
c=8/2
c = 4
a + b + c= 19
8 + b + 4 = 19
12 + b = 19
b=19-12
b = 7
Hence,
a = 8, b = 7, c = 4
Therefore If the perimeter of a triangle is 19 cm. The lengths of 3 sides is: a = 8, b = 7, c = 4.
The complete question is:
Perimeter of triangle is 19cm. If the length of the longest side is twice that of the shortest side and 3 less than the sum of the lengths of the 2 sides find lengths of 3 sides.
Learn more about perimeter here:brainly.com/question/19819849
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