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Sedaia [141]
3 years ago
14

Quadrilateral A B C D is shown. Sides A D and B C are parallel. Sides A B and C D are congruent. Angle A is 115 degrees. What is

the measure of ADC in quadrilateral ABCD? 45° 65° 115° 135°
Mathematics
2 answers:
lilavasa [31]3 years ago
7 0

Answer:

  • 65° if parallelogram
  • 115° if trapezoid

Step-by-step explanation:

<em>Since no diagram attached there are two possible options.</em>

Option 1

The quadrilateral is parallelogram.

<u>In this case ∠A and ∠D sum up to 180°, therefore:</u>

  • ∠ADC = 180° - 115° = 65°

Option 2

The quadrilateral is isosceles trapezoid.

<u>In this case ∠A is congruent with ∠D, therefore:</u>

  • ∠ADC = ∠A = 115°
brilliants [131]3 years ago
4 0

Step-by-step explanation:

Since sides AD and BC are parallel,

Angle BAD + Angle ADC = 180° (co-interior angles)

Therefore Angle ADC = 180° - 115° = 65°.

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The question says,

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