Answer:
13.5 m/s
Step-by-step explanation:
To start off, simply plug in the values into the equation. This is shown below...
<u>v = velocity</u>
<u>u = initial velocity</u>
<u>a = acceleration</u>
<u>t = time</u>
v = u + at ---> v = 3 + 1.5(7)
First, multiply 1.5 and 7 together. By doing so, you get 10.5. Now the equation is...
v = 3 + 10.5
To finish, simply add 3 and 10.5...
v = 3 + 10.5 ---> v = 13.5
<u>Your answer is 13.5 m/s</u>
Answer:
d = 9
Step-by-step explanation:
Given
1 = 
d - 2 ( multiply through by 3 to clear the fraction )
3 = d - 6 ( add 6 to both sides )
9 = d
For
ax²+bx+c
if a≠1 then use the ac method
1. multiply a and c
2. factor the result such that they add to get b
3. split b up into those 2 factors
4. group and undistribute
so
12x²-1x-6
ac=12*-6=-72
what 2 factors add to -1?
-9 and 8
12x²+8x-9x-6
group
(12x²+8x)+(-9x-6)
undistribute
4x(3x+2)+(-3)(3x+2)
undistribute
(4x-3)(3x+2)
1. The number of sample size 1 jelly beans in a 2-liter jar is <u>645</u>.
2. The number of sample size 2 jelly beans in a 2-liter jar is <u>640</u>.
3. The number of sample size 3 jelly beans in a 2-liter jar is <u>637</u>.
<h3>What is a mathematical operation?</h3>
A mathematical operation is an expression involving the use of mathematical operands and operators to compute values.
Mathematical operations use variables, numbers, and operators (addition, subtraction, division, and multiplication).
<h3>Data and Calculations:</h3>
Total weight = 1,150g
Weight of the jar = 440g
The total weight of the jelly beans = 710g (1,150 - 440)
Sample Size 1: the number of jelly beans = 645 (710/22.0 x 20)
Sample Size 2: the number of jelly beans = 640 (710/22.2 x 20)
Sample Size 3: the number of jelly beans = 637 (710/22.3 x 20)
Thus, the number of jelly beans in a 2-liter jar depends on the sample size of the jelly beans.
Learn more about mathematical operations at brainly.com/question/20628271
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